To solve this problem, we need to set up an inequality that represents the scenario described.

Problem Analysis:

• The container can carry a maximum weight of 27,500 kg.
• There is already 6,800 kg of other shipments in the container.
• Each crate weighs 150 kg.
• We need to find the maximum number of crates, $x$, that can still be loaded.

Setting Up the Inequality:

Let $x$ be the number of 150 kg crates. The total weight of these crates will be $150x$.

Since the combined weight of the existing shipments and the crates cannot exceed the maximum allowed weight, we have: $6800 + 150x \leq 27500$

Solving the Inequality:

1. Subtract 6,800 from both sides: $150x \leq 20700$

2. Divide both sides by 150: $x \leq 138$

Thus, the inequality you should enter is: $x \leq 138$

Answer:

• Inequality: $x \leq 138$
• Interpretation: You can load a maximum of 138 crates, each weighing 150 kg, in the container without exceeding the weight limit.

Would you like further details or have questions about this solution?

Here are 5 related questions for further exploration:

1. What if the maximum weight was reduced to 25,000 kg? How would that change the inequality?
2. How would the answer change if each crate weighed 200 kg instead of 150 kg?
3. What if there were no other shipments initially loaded? What would the maximum number of crates be then?
4. Can you calculate the remaining weight capacity if you load 120 crates?
5. What would happen if you exceeded the maximum weight limit? What are potential risks?

Tip: When setting up inequalities, carefully identify all given values and constraints before forming your equation.