Math Problem Statement

A shoe company sells each pair of sneakers for $60 and expects to sell 3,000 pairs at this price. Their sales analysts have predicted the revenue, R, based on the number x, of $5 price increases using the equation R = -750(x - 4)^2 + 192,000. Assuming the sales analysts have predicted the revenue accurately, for what price should the shoe company sell each pair of sneakers in order to earn the maximum revenue?

Solution

We are given the revenue equation R=750(x4)2+192,000R = -750(x - 4)^2 + 192,000, where xx represents the number of $5 price increases from the initial price of $60.

To solve this:

Step 1: Identify the vertex of the quadratic function

The equation is already in vertex form: R=750(x4)2+192,000R = -750(x - 4)^2 + 192,000 The vertex of a quadratic function in the form R=a(xh)2+kR = a(x - h)^2 + k occurs at x=hx = h, and the maximum value of RR occurs at that point if a<0a < 0.

Here, h=4h = 4, meaning that the maximum revenue occurs when x=4x = 4.

Step 2: Calculate the price at maximum revenue

The price increases in steps of $5. Initially, the price was $60. Each increase corresponds to an increment of $5, so for x=4x = 4:

New price=60+4×5=60+20=80\text{New price} = 60 + 4 \times 5 = 60 + 20 = 80

Thus, the shoe company should sell each pair of sneakers for $80 to earn the maximum revenue.

The correct answer is:

d.80per pair of sneakers\boxed{d. \, 80 \, \text{per pair of sneakers}}


Would you like more details or have any other questions?

Here are 5 related questions to further your understanding:

  1. How do we determine whether a quadratic equation represents a maximum or minimum?
  2. What are the implications of changing the price on the number of units sold?
  3. How can we interpret the vertex form of a quadratic equation in real-world problems?
  4. What other types of models can be used to predict revenue based on price changes?
  5. Why does increasing the price beyond a certain point decrease total revenue?

Tip: Quadratic functions always have a maximum or minimum, depending on the coefficient of the squared term, which is key in optimizing real-world problems!

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Revenue Maximization

Formulas

Vertex form of a quadratic equation: R = a(x - h)^2 + k

Theorems

The vertex of a parabola gives the maximum or minimum point in a quadratic function when a < 0

Suitable Grade Level

Grades 9-12