Math Problem Statement

a rectangular plot of land is to be fenced in using two kinds of fencing. two opposite sides will use heavy-duty fencing selling for $5 a foot, while the remaining two sides will use standard fencing selling for $2 a foot. what are the dimensions of the rectangular plot of a greatest area that can be fenced in at a cost of $11000?

__ ft of heavy duty fencing __ ft of standard fencing

Solution

Let's solve the problem step by step.

Step 1: Define Variables

Let:

  • xx be the length of the rectangular plot (in feet),
  • yy be the width of the rectangular plot (in feet).

Step 2: Cost Equation

We are given that:

  • The two opposite sides of the rectangle will use heavy-duty fencing, costing $5 per foot.
  • The other two opposite sides will use standard fencing, costing $2 per foot.

The total cost of fencing is $11,000. The cost for the heavy-duty fencing will be for the two sides of length xx, and the cost for the standard fencing will be for the two sides of length yy.

Thus, the cost equation is: 5(2x)+2(2y)=110005(2x) + 2(2y) = 11000 Simplifying: 10x+4y=1100010x + 4y = 11000

Step 3: Area Equation

The area of the rectangular plot is given by: A=xyA = x \cdot y We want to maximize this area.

Step 4: Solve the Cost Equation for One Variable

From the cost equation: 10x+4y=1100010x + 4y = 11000 Solve for yy in terms of xx: 4y=1100010x4y = 11000 - 10x y=1100010x4y = \frac{11000 - 10x}{4} y=27502.5xy = 2750 - 2.5x

Step 5: Substitute yy into the Area Formula

Substitute y=27502.5xy = 2750 - 2.5x into the area formula A=xyA = x \cdot y: A(x)=x(27502.5x)A(x) = x(2750 - 2.5x) A(x)=2750x2.5x2A(x) = 2750x - 2.5x^2

Step 6: Maximize the Area

To maximize the area, we take the derivative of A(x)A(x) with respect to xx and set it equal to 0: dAdx=27505x\frac{dA}{dx} = 2750 - 5x Set the derivative equal to 0: 27505x=02750 - 5x = 0 Solving for xx: x=27505=550x = \frac{2750}{5} = 550

Step 7: Find yy

Substitute x=550x = 550 into the equation for yy: y=27502.5(550)y = 2750 - 2.5(550) y=27501375=1375y = 2750 - 1375 = 1375

Step 8: Verify the Cost

Now, verify that the total cost is $11,000:

  • The cost of the two heavy-duty sides is 10x=10(550)=550010x = 10(550) = 5500 dollars.
  • The cost of the two standard sides is 4y=4(1375)=55004y = 4(1375) = 5500 dollars.

Total cost: 5500+5500=11000dollars5500 + 5500 = 11000 \, \text{dollars} This matches the given cost.

Final Answer:

  • Heavy-duty fencing: 1100 feet (since 2x=2(550)2x = 2(550))
  • Standard fencing: 2750 feet (since 2y=2(1375)2y = 2(1375))

Would you like more details or further explanations? Here are some related questions:

  1. How would the area change if we used only heavy-duty fencing for all four sides?
  2. What happens if the cost of heavy-duty fencing increases to $6 per foot?
  3. How do we calculate the maximum area if the total cost of fencing is reduced to $8000?
  4. What is the formula to calculate the total cost based on different lengths of fencing?
  5. How do you find the dimensions of a rectangle that maximizes area given a fixed perimeter?

Tip: When optimizing a function like the area, the derivative helps to find the critical points where the maximum or minimum might occur. Always check the second derivative to confirm if it’s a maximum!

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Math Problem Analysis

Mathematical Concepts

Algebra
Optimization
Cost Calculation
Area of Rectangle

Formulas

Cost equation: 10x + 4y = 11000
Area equation: A = x * y
Maximization using derivatives: A'(x) = 2750 - 5x

Theorems

Optimization using derivatives

Suitable Grade Level

Grades 10-12