Math Problem Statement

The Ride This skate board factory produces Mega skateboards and Supreme skateboards. their maximum output is 40 skateboards a day and they must produce at least 3 times as many Mega boards as Supreme boards. the profit on a Mega skateboard is $55 and the profit on a Supreme skateboard is $75. What is the factory's maximum daily profit?

Solution

To solve this problem, we need to set up a system of inequalities and an objective function to maximize the daily profit of the skateboard factory.

Step 1: Define Variables

  • Let MM represent the number of Mega skateboards produced daily.
  • Let SS represent the number of Supreme skateboards produced daily.

Step 2: Write the Constraints

  1. The total number of skateboards produced cannot exceed 40: M+S40M + S \leq 40

  2. The factory must produce at least 3 times as many Mega skateboards as Supreme skateboards: M3SM \geq 3S

  3. Both MM and SS must be non-negative: M0andS0M \geq 0 \quad \text{and} \quad S \geq 0

Step 3: Define the Objective Function

  • The profit from Mega skateboards is $55 per board, so the profit from MM Mega skateboards is 55M55M.
  • The profit from Supreme skateboards is $75 per board, so the profit from SS Supreme skateboards is 75S75S.

The objective function (total profit PP) to maximize is: P=55M+75SP = 55M + 75S

Step 4: Solve the System of Inequalities We need to find the values of MM and SS that maximize P=55M+75SP = 55M + 75S under the constraints.

Step 5: Check the Vertices of the Feasible Region The feasible region is determined by the constraints:

  1. M+S=40M + S = 40
  2. M=3SM = 3S

Now, let's find the intersection points:

  1. Set M=3SM = 3S into M+S=40M + S = 40: 3S+S=40    4S=40    S=103S + S = 40 \implies 4S = 40 \implies S = 10 Substituting S=10S = 10 into M=3SM = 3S: M=3×10=30M = 3 \times 10 = 30 So, one vertex is (M,S)=(30,10)(M, S) = (30, 10).

  2. Other vertices are found by testing when S=0S = 0:

    • If S=0S = 0, then M+0=40M + 0 = 40 implies M=40M = 40.
    • If M=0M = 0, then S=0S = 0 because M=3SM = 3S.

Step 6: Evaluate the Profit at Each Vertex

  1. At (M,S)=(30,10)(M, S) = (30, 10): P=55×30+75×10=1650+750=2400P = 55 \times 30 + 75 \times 10 = 1650 + 750 = 2400

  2. At (M,S)=(40,0)(M, S) = (40, 0): P=55×40+75×0=2200P = 55 \times 40 + 75 \times 0 = 2200

  3. At (M,S)=(0,0)(M, S) = (0, 0): P=55×0+75×0=0P = 55 \times 0 + 75 \times 0 = 0

Step 7: Conclusion The maximum profit occurs at (M,S)=(30,10)(M, S) = (30, 10), with a maximum daily profit of:

2400\boxed{2400}

Would you like more details on any part of this solution, or do you have any questions?

Here are some related questions for further exploration:

  1. How would the maximum profit change if the profit per Mega skateboard increased to $60?
  2. What would happen to the maximum profit if the constraint M3SM \geq 3S changed to M2SM \geq 2S?
  3. How would

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Math Problem Analysis

Mathematical Concepts

Linear Programming
Inequalities
Optimization

Formulas

M + S ≤ 40 (total skateboard production constraint)
M ≥ 3S (production ratio constraint)
P = 55M + 75S (objective function to maximize profit)

Theorems

Vertex Theorem in Linear Programming

Suitable Grade Level

Grades 10-12