Math Problem Statement

Consider two non-negative numbers
x and
y such that
x + y

10 . What is the maximal value of the quantity
x 2 y 2 ?

Solution

To find the maximal value of the quantity x2y2x^2 y^2 given that x+y=10x + y = 10, we can use the method of calculus or the Arithmetic Mean-Geometric Mean (AM-GM) inequality.

Step 1: Express the function to maximize

We are given: x+y=10x + y = 10 We want to maximize: f(x,y)=x2y2f(x, y) = x^2 y^2 We can express yy in terms of xx: y=10xy = 10 - x Thus, the function becomes: f(x)=x2(10x)2f(x) = x^2 (10 - x)^2

Step 2: Simplify the function

Let's expand the function: f(x)=x2(10020x+x2)f(x) = x^2 (100 - 20x + x^2) f(x)=x2(x220x+100)f(x) = x^2 (x^2 - 20x + 100) f(x)=x420x3+100x2f(x) = x^4 - 20x^3 + 100x^2

Step 3: Take the derivative and find critical points

To maximize f(x)f(x), take the derivative with respect to xx: f(x)=4x360x2+200xf'(x) = 4x^3 - 60x^2 + 200x Set the derivative equal to zero to find critical points: 4x360x2+200x=04x^3 - 60x^2 + 200x = 0 Factor out 4x4x: 4x(x215x+50)=04x(x^2 - 15x + 50) = 0 This gives us: x=0orx215x+50=0x = 0 \quad \text{or} \quad x^2 - 15x + 50 = 0

Step 4: Solve the quadratic equation

For the quadratic equation: x215x+50=0x^2 - 15x + 50 = 0 Use the quadratic formula: x=(15)±(15)24(1)(50)2(1)x = \frac{-(-15) \pm \sqrt{(-15)^2 - 4(1)(50)}}{2(1)} x=15±2252002x = \frac{15 \pm \sqrt{225 - 200}}{2} x=15±252x = \frac{15 \pm \sqrt{25}}{2} x=15±52x = \frac{15 \pm 5}{2} Thus: x=10orx=5x = 10 \quad \text{or} \quad x = 5

Step 5: Evaluate the function at critical points

For x=0x = 0: f(0)=02×(100)2=0f(0) = 0^2 \times (10 - 0)^2 = 0 For x=10x = 10: f(10)=102×(1010)2=0f(10) = 10^2 \times (10 - 10)^2 = 0 For x=5x = 5 (and y=5y = 5): f(5)=52×52=25×25=625f(5) = 5^2 \times 5^2 = 25 \times 25 = 625

Conclusion

The maximal value of x2y2x^2 y^2 occurs when x=5x = 5 and y=5y = 5, and the maximal value is: 625\boxed{625}

Would you like more details or have any questions?

Here are five related questions to expand your understanding:

  1. What is the minimal value of x2y2x^2 y^2 given the same conditions?
  2. How would the maximal value change if x+y=20x + y = 20 instead of 10?
  3. Can the AM-GM inequality be used directly to solve this problem? How?
  4. What happens if x+yx + y is a variable instead of a fixed number?
  5. How can this problem be extended to maximize xnynx^n y^n for any positive integer nn?

Tip: Always check if there is a simpler method, like using inequalities, before jumping into calculus for optimization problems.

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Math Problem Analysis

Mathematical Concepts

Calculus
Arithmetic Mean-Geometric Mean (AM-GM) inequality

Formulas

Quadratic equation formula
Derivative formula

Theorems

AM-GM inequality

Suitable Grade Level

Grades 11-12