Math Problem Statement

A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. Using this equation, find out the maximum amount of profit the company can make, to the nearest dollar. y, equals, minus, x, squared, plus, 84, x, minus, 630 y=−x 2 +84x−630

Solution

To find the maximum profit, we need to determine the vertex of the quadratic equation y=x2+84x630y = -x^2 + 84x - 630. The vertex of a parabola described by y=ax2+bx+cy = ax^2 + bx + c occurs at x=b2ax = -\frac{b}{2a}.

Here:

  • a=1a = -1
  • b=84b = 84
  • c=630c = -630

Step 1: Find xx at the vertex

x=b2a=842(1)=842=42x = -\frac{b}{2a} = -\frac{84}{2(-1)} = \frac{84}{2} = 42

Step 2: Substitute x=42x = 42 into the equation to find yy

y=(42)2+84(42)630y = -(42)^2 + 84(42) - 630

Calculate each term: (42)2=1764-(42)^2 = -1764 84×42=352884 \times 42 = 3528 y=1764+3528630y = -1764 + 3528 - 630 y=1134y = 1134

Final Answer:

The maximum profit is $1,134.

Would you like a detailed breakdown of any step or have additional questions?


5 Related Questions:

  1. What is the significance of the vertex in real-world applications like profit maximization?
  2. How does the coefficient of x2x^2 affect the shape of the graph of this profit function?
  3. What does the xx-coordinate of the vertex represent in this scenario?
  4. Could you find the selling price of each widget that yields the maximum profit?
  5. How would the equation change if fixed costs increased by $100?

Tip: For profit optimization problems, always check whether the quadratic function opens upwards (a>0a > 0) or downwards (a<0a < 0) to determine whether you're finding a maximum or minimum.

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Vertex of a Parabola
Profit Maximization

Formulas

y = ax^2 + bx + c
x = -b / 2a (vertex formula)

Theorems

Vertex Theorem for Quadratic Functions

Suitable Grade Level

Grades 9-12