Math Problem Statement

Найти максимальную область определения и множество значений следующих функций (представляя функции в виде композиции простых): (a) f(x) = x^2 / (x^2 + 1); (b) f(x) = √(x(4 - x)).

Solution

The task is to find the maximal domain and the range of the following functions, expressed as compositions of simpler functions:

(a) f(x)=x2x2+1f(x) = \frac{x^2}{x^2 + 1}

Domain:

This function is a rational function. Since the denominator x2+1x^2 + 1 is always positive for all real xx, there are no restrictions on xx. Therefore, the domain is: D(f)=RD(f) = \mathbb{R} (all real numbers).

Range:

Let's analyze the behavior of f(x)=x2x2+1f(x) = \frac{x^2}{x^2 + 1}:

  • As xx \to \infty, f(x)1f(x) \to 1.
  • As x0x \to 0, f(0)=0f(0) = 0.
  • f(x)f(x) is symmetric about the y-axis (even function), and its value increases as x|x| increases from 0 to infinity.

Since 0f(x)<10 \leq f(x) < 1 for all xRx \in \mathbb{R}, the range is: R(f)=[0,1)R(f) = [0, 1)


(b) f(x)=x(4x)f(x) = \sqrt{x(4 - x)}

Domain:

To ensure the function is real, the expression under the square root must be non-negative: x(4x)0x(4 - x) \geq 0 This is a quadratic inequality. The roots of the equation x(4x)=0x(4 - x) = 0 are x=0x = 0 and x=4x = 4. The quadratic opens downwards, meaning x(4x)0x(4 - x) \geq 0 for 0x40 \leq x \leq 4. Therefore, the domain is: D(f)=[0,4]D(f) = [0, 4]

Range:

The expression inside the square root is a parabola with its maximum at x=2x = 2, where: f(2)=2(42)=4=2f(2) = \sqrt{2(4 - 2)} = \sqrt{4} = 2

  • At x=0x = 0, f(0)=0=0f(0) = \sqrt{0} = 0.
  • At x=4x = 4, f(4)=0=0f(4) = \sqrt{0} = 0.

Thus, the range of the function is: R(f)=[0,2]R(f) = [0, 2]


Would you like further details on these solutions, or have any specific questions?

Related Questions:

  1. How would the domain and range change if the function in part (a) were modified to x3x2+1\frac{x^3}{x^2 + 1}?
  2. Can you graph the function f(x)=x2x2+1f(x) = \frac{x^2}{x^2 + 1} and describe its critical points?
  3. What is the effect of adding a constant inside the square root in part (b), like x(4x)+1\sqrt{x(4 - x) + 1}?
  4. How can you find the inverse function for f(x)=x2x2+1f(x) = \frac{x^2}{x^2 + 1}, if it exists?
  5. If you shift the quadratic inside the square root to x(5x)\sqrt{x(5 - x)}, how does that affect the domain and range?

Tip:

Always check for restrictions in the domain by analyzing the denominator (in rational functions) or expressions under square roots and logarithms.

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Math Problem Analysis

Mathematical Concepts

Functions
Domain and Range
Rational Functions
Quadratic Inequalities
Square Roots

Formulas

f(x) = x^2 / (x^2 + 1)
f(x) = √(x(4 - x))

Theorems

Properties of Rational Functions
Analysis of Quadratic Inequalities

Suitable Grade Level

Grades 9-12