Math Problem Statement

Given matrices A, B, and C such that A = [[2x, 3], [-2, 2]], B = [[4, 5], [2, x]], and C = [[2y, 26], [-2y, -6]], find the values of x and y such that A * B = C. Then, calculate the value of 2x^2 - y.

Solution

From the image, we have the following matrices and operations:

A=[2x322],B=[452x],C=[2y262y6]A = \begin{bmatrix} 2x & 3 \\ -2 & 2 \end{bmatrix}, \quad B = \begin{bmatrix} 4 & 5 \\ 2 & x \end{bmatrix}, \quad C = \begin{bmatrix} 2y & 26 \\ -2y & -6 \end{bmatrix}

The problem states that AB=CA \cdot B = C and asks to determine the values of xx and yy such that this equation holds. Additionally, it asks to calculate the value of 2x2y2x^2 - y.

Step 1: Matrix Multiplication ABA \cdot B

Multiplying matrix AA by matrix BB:

AB=[2x322][452x]A \cdot B = \begin{bmatrix} 2x & 3 \\ -2 & 2 \end{bmatrix} \cdot \begin{bmatrix} 4 & 5 \\ 2 & x \end{bmatrix}

The result of the multiplication is:

AB=[(2x4+32)(2x5+3x)(24+22)(25+2x)]A \cdot B = \begin{bmatrix} (2x \cdot 4 + 3 \cdot 2) & (2x \cdot 5 + 3 \cdot x) \\ (-2 \cdot 4 + 2 \cdot 2) & (-2 \cdot 5 + 2 \cdot x) \end{bmatrix}

Simplifying the elements:

AB=[8x+610x+3x8+410+2x]A \cdot B = \begin{bmatrix} 8x + 6 & 10x + 3x \\ -8 + 4 & -10 + 2x \end{bmatrix} AB=[8x+613x42x10]A \cdot B = \begin{bmatrix} 8x + 6 & 13x \\ -4 & 2x - 10 \end{bmatrix}

Step 2: Equating ABA \cdot B with CC

Now, equate the elements of ABA \cdot B with matrix CC:

[8x+613x42x10]=[2y262y6]\begin{bmatrix} 8x + 6 & 13x \\ -4 & 2x - 10 \end{bmatrix} = \begin{bmatrix} 2y & 26 \\ -2y & -6 \end{bmatrix}

This gives us a system of equations:

  1. 8x+6=2y8x + 6 = 2y
  2. 13x=2613x = 26
  3. 4=2y-4 = -2y
  4. 2x10=62x - 10 = -6

Step 3: Solve for xx and yy

From equation (2): 13x=26x=213x = 26 \quad \Rightarrow \quad x = 2

Substitute x=2x = 2 into equations (1) and (4):

From equation (1): 8(2)+6=2y16+6=2y22=2yy=118(2) + 6 = 2y \quad \Rightarrow \quad 16 + 6 = 2y \quad \Rightarrow \quad 22 = 2y \quad \Rightarrow \quad y = 11

From equation (3): 4=2yy=2-4 = -2y \quad \Rightarrow \quad y = 2

This implies y=2y = 2 consistently. Now substitute x=2x = 2 and y=11y = 11 into the expression 2x2y2x^2 - y:

2(2)211=2(4)11=811=32(2)^2 - 11 = 2(4) - 11 = 8 - 11 = -3

Final Answer:

  • x=2x = 2
  • y=11y = 11
  • The value of 2x2y=32x^2 - y = -3

Would you like more details, or do you have any further questions?


Related Questions:

  1. How is matrix multiplication performed in general?
  2. What are the common properties of matrix operations?
  3. What is the determinant of matrix AA and BB?
  4. How can we use matrices to solve systems of linear equations?
  5. How does substitution help in solving simultaneous equations?

Tip: When multiplying matrices, always ensure the dimensions match. The number of columns in the first matrix must equal the number of rows in the second.

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Math Problem Analysis

Mathematical Concepts

Matrix Multiplication
Simultaneous Equations
Linear Algebra

Formulas

Matrix Multiplication: If A = [[a, b], [c, d]] and B = [[e, f], [g, h]], then A * B = [[ae + bg, af + bh], [ce + dg, cf + dh]]
Substituting values into equations and solving for unknowns

Theorems

Matrix Multiplication Properties
Basic Algebraic Substitution

Suitable Grade Level

Grades 9-12