Math Problem Statement

yes, no , maybe. If the equation 𝐴 𝑥

0 Ax=0 has a nontrivial solution, then 𝐴 A has fewer than 𝑛 n pivots. If 𝐴 A is not invertible, then 𝐴 2 A 2 is also not invertible. If the linear transformation 𝑇 𝐴 T A ​ is one-to-one, then the columns of 𝐴 A form a linearly dependent set. If the linear transformation 𝑇 𝐴 T A ​ is onto, then it is also one-to-one. If the equation 𝐴 𝑥

0 Ax=0 has the trivial solution, then the columns of 𝐴 A span 𝑅 𝑛 R n . If 𝐴 A is not invertible, then 𝐴 7 A 7 is also not invertible.

Solution

Let’s analyze each of these statements and clarify whether they are true or false:

  1. If the equation Ax=0A x = 0 has a nontrivial solution, then AA has fewer than nn pivots.

    True: If Ax=0A x = 0 has a nontrivial solution, then the matrix AA has at least one free variable, meaning it is not full-rank. This implies that AA has fewer than nn pivots (where nn is the number of columns of AA).

  2. If AA is not invertible, then A2A^2 is also not invertible.

    True: If AA is not invertible, then AA has a determinant of zero. The matrix A2=A×AA^2 = A \times A will also have a determinant of zero, making A2A^2 not invertible as well.

  3. If the linear transformation TAT_A is one-to-one, then the columns of AA form a linearly dependent set.

    False: If the transformation TAT_A is one-to-one, it implies that the equation Ax=0A x = 0 has only the trivial solution. This means the columns of AA are linearly independent, not dependent.

  4. If the linear transformation TAT_A is onto, then it is also one-to-one.

    False: A linear transformation can be onto (surjective) without being one-to-one (injective). Surjectivity implies that every element in the codomain is mapped by at least one element in the domain, but it doesn't necessarily mean that each element in the domain maps to a unique element.

  5. If the equation Ax=0A x = 0 has the trivial solution, then the columns of AA span Rn\mathbb{R}^n.

    False: The equation Ax=0A x = 0 having the trivial solution (i.e., x=0x = 0 being the only solution) means that the columns are linearly independent, but this does not necessarily imply that they span Rn\mathbb{R}^n. The matrix must be square (and invertible) for the columns to span Rn\mathbb{R}^n.

  6. If AA is not invertible, then A7A^7 is also not invertible.

    True: If AA is not invertible, then AA has a determinant of zero. Any power of AA, including A7A^7, will still have a determinant of zero, making it non-invertible.

Would you like more details or have any specific questions?


Here are 5 related questions you can explore:

  1. What are the conditions for a matrix to be invertible?
  2. How does the rank of a matrix relate to the number of pivots it has?
  3. What is the difference between a transformation being one-to-one and onto?
  4. How does the determinant of a matrix behave under matrix multiplication and exponentiation?
  5. What is the relationship between linear dependence and the spanning of a vector space?

Tip: If a matrix has linearly independent columns, it is automatically one-to-one and invertible.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrix Invertibility
Linear Transformations
Pivots and Rank
Linear Independence
Matrix Powers

Formulas

Ax = 0
Determinant of A^n
Rank of a Matrix
Linear Transformation Properties

Theorems

Rank-Nullity Theorem
Invertibility Theorem
Fundamental Theorem of Linear Transformations

Suitable Grade Level

Undergraduate Mathematics