Math Problem Statement
yes, no , maybe. If the equation 𝐴 𝑥
0 Ax=0 has a nontrivial solution, then 𝐴 A has fewer than 𝑛 n pivots. If 𝐴 A is not invertible, then 𝐴 2 A 2 is also not invertible. If the linear transformation 𝑇 𝐴 T A is one-to-one, then the columns of 𝐴 A form a linearly dependent set. If the linear transformation 𝑇 𝐴 T A is onto, then it is also one-to-one. If the equation 𝐴 𝑥
0 Ax=0 has the trivial solution, then the columns of 𝐴 A span 𝑅 𝑛 R n . If 𝐴 A is not invertible, then 𝐴 7 A 7 is also not invertible.
Solution
Let’s analyze each of these statements and clarify whether they are true or false:
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If the equation has a nontrivial solution, then has fewer than pivots.
True: If has a nontrivial solution, then the matrix has at least one free variable, meaning it is not full-rank. This implies that has fewer than pivots (where is the number of columns of ).
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If is not invertible, then is also not invertible.
True: If is not invertible, then has a determinant of zero. The matrix will also have a determinant of zero, making not invertible as well.
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If the linear transformation is one-to-one, then the columns of form a linearly dependent set.
False: If the transformation is one-to-one, it implies that the equation has only the trivial solution. This means the columns of are linearly independent, not dependent.
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If the linear transformation is onto, then it is also one-to-one.
False: A linear transformation can be onto (surjective) without being one-to-one (injective). Surjectivity implies that every element in the codomain is mapped by at least one element in the domain, but it doesn't necessarily mean that each element in the domain maps to a unique element.
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If the equation has the trivial solution, then the columns of span .
False: The equation having the trivial solution (i.e., being the only solution) means that the columns are linearly independent, but this does not necessarily imply that they span . The matrix must be square (and invertible) for the columns to span .
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If is not invertible, then is also not invertible.
True: If is not invertible, then has a determinant of zero. Any power of , including , will still have a determinant of zero, making it non-invertible.
Would you like more details or have any specific questions?
Here are 5 related questions you can explore:
- What are the conditions for a matrix to be invertible?
- How does the rank of a matrix relate to the number of pivots it has?
- What is the difference between a transformation being one-to-one and onto?
- How does the determinant of a matrix behave under matrix multiplication and exponentiation?
- What is the relationship between linear dependence and the spanning of a vector space?
Tip: If a matrix has linearly independent columns, it is automatically one-to-one and invertible.
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Math Problem Analysis
Mathematical Concepts
Linear Algebra
Matrix Invertibility
Linear Transformations
Pivots and Rank
Linear Independence
Matrix Powers
Formulas
Ax = 0
Determinant of A^n
Rank of a Matrix
Linear Transformation Properties
Theorems
Rank-Nullity Theorem
Invertibility Theorem
Fundamental Theorem of Linear Transformations
Suitable Grade Level
Undergraduate Mathematics
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