Math Problem Statement

. Reduce the matrix 𝐴 = [ βˆ’1 2 βˆ’2 1 2 1 βˆ’1 βˆ’1 0 ] to the diagonal form.

Solution

To reduce matrix AA to its diagonal form, we'll follow these steps:

The given matrix is: A=[βˆ’12βˆ’2121βˆ’1βˆ’10]A = \begin{bmatrix} -1 & 2 & -2 \\ 1 & 2 & 1 \\ -1 & -1 & 0 \end{bmatrix}

We'll use row operations to convert this matrix to its diagonal form.

Let's perform Gaussian elimination to achieve this:

  1. First, make the pivot element in the first row and first column as 1:

Multiply the first row by βˆ’1-1: [1βˆ’22121βˆ’1βˆ’10]\begin{bmatrix} 1 & -2 & 2 \\ 1 & 2 & 1 \\ -1 & -1 & 0 \end{bmatrix}

  1. Eliminate the other elements in the first column:

Subtract row 1 from row 2: [1βˆ’2204βˆ’1βˆ’1βˆ’10]\begin{bmatrix} 1 & -2 & 2 \\ 0 & 4 & -1 \\ -1 & -1 & 0 \end{bmatrix}

Add row 1 to row 3: [1βˆ’2204βˆ’10βˆ’32]\begin{bmatrix} 1 & -2 & 2 \\ 0 & 4 & -1 \\ 0 & -3 & 2 \end{bmatrix}

  1. Make the pivot element in the second row and second column as 1:

Divide the second row by 4: [1βˆ’2201βˆ’140βˆ’32]\begin{bmatrix} 1 & -2 & 2 \\ 0 & 1 & -\frac{1}{4} \\ 0 & -3 & 2 \end{bmatrix}

  1. Eliminate the other elements in the second column:

Add 2 times the second row to the first row: [105201βˆ’140βˆ’32]\begin{bmatrix} 1 & 0 & \frac{5}{2} \\ 0 & 1 & -\frac{1}{4} \\ 0 & -3 & 2 \end{bmatrix}

Add 3 times the second row to the third row: [105201βˆ’140054]\begin{bmatrix} 1 & 0 & \frac{5}{2} \\ 0 & 1 & -\frac{1}{4} \\ 0 & 0 & \frac{5}{4} \end{bmatrix}

  1. Make the pivot element in the third row and third column as 1:

Multiply the third row by 45\frac{4}{5}: [105201βˆ’14001]\begin{bmatrix} 1 & 0 & \frac{5}{2} \\ 0 & 1 & -\frac{1}{4} \\ 0 & 0 & 1 \end{bmatrix}

  1. Eliminate the other elements in the third column:

Subtract 52\frac{5}{2} times the third row from the first row: [10001βˆ’14001]\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & -\frac{1}{4} \\ 0 & 0 & 1 \end{bmatrix}

Add 14\frac{1}{4} times the third row to the second row: [100010001]\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}

Thus, the matrix is now in diagonal form: A=[100010001]A = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}

The final diagonal matrix is the identity matrix.

Would you like a further explanation or have any questions?

Relative Questions:

  1. What is the purpose of reducing a matrix to diagonal form?
  2. How does Gaussian elimination differ from Gauss-Jordan elimination?
  3. Can all matrices be reduced to a diagonal form?
  4. What are the implications of a matrix being reducible to the identity matrix?
  5. How can eigenvalues be found from the diagonal form?

Tip:

Diagonal matrices are extremely useful in simplifying matrix operations, as multiplying with a diagonal matrix is much faster than with a general matrix.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrix Diagonalization
Gaussian Elimination

Formulas

Row operations for Gaussian Elimination
Diagonal matrix form A' = diag(Ξ»1, Ξ»2, ..., Ξ»n)

Theorems

Gaussian Elimination Theorem
Diagonalization Theorem

Suitable Grade Level

Undergraduate