Math Problem Statement

Match each equation to its graph.

Solution

This problem asks you to match each equation to its corresponding graph. Each equation given is a linear function of the form y=mxy = mx, where mm is the slope of the line. Let's go through the process of identifying the correct matches by observing the slopes from both the equations and the graphs.


Step 1: Equation Slopes

Below are the equations and their slopes:

  • a.y=2x(m=2)a. \quad y = 2x \quad (m = 2)
  • b.y=45x(m=45)b. \quad y = \frac{4}{5}x \quad (m = \frac{4}{5})
  • c.y=14x(m=14)c. \quad y = \frac{1}{4}x \quad (m = \frac{1}{4})
  • d.y=23x(m=23)d. \quad y = \frac{2}{3}x \quad (m = \frac{2}{3})
  • e.y=34x(m=34)e. \quad y = \frac{3}{4}x \quad (m = \frac{3}{4})
  • f.y=32x(m=32)f. \quad y = \frac{3}{2}x \quad (m = \frac{3}{2})

Step 2: Identify Graph Slopes

Now, we need to determine the rise over run (slope) from each graph.

  1. Graph 1: Rise = 5, Run = 4 → Slope m=54m = \frac{5}{4}. (This matches none of the given equations perfectly since no equation has 54x\frac{5}{4}x).
  2. Graph 2: Rise = 2, Run = 3 → Slope m=23m = \frac{2}{3}. (Matches d. y=23xy = \frac{2}{3}x).
  3. Graph 3: Rise = 3, Run = 2 → Slope m=32m = \frac{3}{2}. (Matches f. y=32xy = \frac{3}{2}x).
  4. Graph 4: Rise = 1, Run = 4 → Slope m=14m = \frac{1}{4}. (Matches c. y=14xy = \frac{1}{4}x).
  5. Graph 5: Rise = 3, Run = 4 → Slope m=34m = \frac{3}{4}. (Matches e. y=34xy = \frac{3}{4}x).
  6. Graph 6: Rise = 4, Run = 5 → Slope m=45m = \frac{4}{5}. (Matches b. y=45xy = \frac{4}{5}x).

Step 3: Matching Results

Based on the above analysis:

  • Graph 2d.y=23xd. \quad y = \frac{2}{3}x
  • Graph 3f.y=32xf. \quad y = \frac{3}{2}x
  • Graph 4c.y=14xc. \quad y = \frac{1}{4}x
  • Graph 5e.y=34xe. \quad y = \frac{3}{4}x
  • Graph 6b.y=45xb. \quad y = \frac{4}{5}x

Note: Graph 1 has a slope of 54\frac{5}{4}, which does not directly match any equation. However, it seems the closest matching equation might be a.y=2xa. \quad y = 2x, though the slope is not exactly aligned.


Final Matches:

  • Graph 1: a.y=2xa. \quad y = 2x (approximate match)
  • Graph 2: d.y=23xd. \quad y = \frac{2}{3}x
  • Graph 3: f.y=32xf. \quad y = \frac{3}{2}x
  • Graph 4: c.y=14xc. \quad y = \frac{1}{4}x
  • Graph 5: e.y=34xe. \quad y = \frac{3}{4}x
  • Graph 6: b.y=45xb. \quad y = \frac{4}{5}x

Do you need any further clarification or help?
Here are five follow-up questions you might consider:

  1. How do you calculate the slope between two points on a graph?
  2. What would the equation look like if the slope were negative?
  3. How can we determine the y-intercept of a line from a graph?
  4. Why does a greater slope result in a steeper line?
  5. What happens to the graph if we multiply the slope by a negative number?

Tip: To quickly estimate the slope from a graph, pick two points on the line, and use m=riserunm = \frac{\text{rise}}{\text{run}}.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Graphing

Formulas

Slope formula m = rise/run

Theorems

Linear function theorem

Suitable Grade Level

Grades 7-9