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The question is asking about the odds of winning if the lottery has 54 numbers instead of 53, with one winning ticket.

To find the odds, we calculate the number of possible combinations of 53 numbers chosen from 54 (assuming this is a typical lottery system).

The formula to calculate combinations is:

\[
C(n, k) = \frac{n!}{k!(n - k)!}
\]

Where:
- \( n \) is the total number of items (in this case, 54),
- \( k \) is the number of items chosen (in this case, 53).

So, the total number of combinations would be:

\[
C(54, 53) = \frac{54!}{53!(54 - 53)!} = \frac{54!}{53!1!} = 54
\]

Thus, the odds of winning would be 1 in 54, which is slightly worse than 1 in 53, meaning the total odds would increase slightly.

However, the listed options in the image seem to be standard lottery odds, so the correct choice should be 1:25,827,165, which corresponds to a large-scale lottery system where the odds are much higher for a typical lottery.

**The correct answer is:** 
- **1:25,827,165**

Would you like further details or calculations?

What would the odds of winning be if there are 54 numbers instead of 53 with one winning ticket?

Find out how to calculate the lottery odds when the number of possible numbers increases from 53 to 54. Using probability and combinatorics, this detailed guide will walk you through the steps and provide the correct answer to this high school-level math question.

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