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This image depicts a long division problem setup. The number on the left side of the bracket is 3, while the number inside the bracket appears to be 11585. The division is likely trying to determine how many times 3 goes into 11585. The layout follows standard division steps, where each part of the quotient and remainder is calculated progressively.

Here’s how to perform the division:

1. Start with the first digit (1): \( 3 \) does not go into \( 1 \), so proceed to the next two digits.
2. Now look at 11: \( 3 \) goes into \( 11 \) three times (with a remainder of \( 11 - 9 = 2 \)).
3. Bring down the next digit (5), making it 25: \( 3 \) goes into \( 25 \) eight times (with a remainder of \( 25 - 24 = 1 \)).
4. Bring down the next digit (8), making it 18: \( 3 \) goes into \( 18 \) exactly six times (remainder \( 0 \)).
5. Finally, bring down the last digit (5): \( 3 \) goes into \( 5 \) one time (with a remainder of \( 5 - 3 = 2 \)).
6. The final remainder is \( 2 \).

The complete quotient is likely \( 3861 \), with a remainder of 2.

Would you like a more detailed step-by-step solution or further assistance? Here are some related questions for you:

1. How do we handle remainders in long division problems?
2. Can you explain the concept of divisibility in greater detail?
3. What happens when the divisor is larger than the number being divided?
4. How would this division look using other methods, like synthetic division?
5. What is the relationship between long division and fractions?

**Tip:** Always bring down digits one by one in long division and proceed step-by-step to avoid confusion.

Perform long division for 11585 divided by 3.

Learn how to solve the long division problem 11585 ÷ 3 with a detailed step-by-step solution. This problem demonstrates the process of dividing, calculating quotients, and determining remainders. Suitable for students in Grades 4-6.

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