To solve the expression \( \log_2 11 - \log_2 9 \), we can use the property of logarithms that states:

\[
\log_a b - \log_a c = \log_a \left(\frac{b}{c}\right)
\]

Applying this property, we have:

\[
\log_2 11 - \log_2 9 = \log_2 \left(\frac{11}{9}\right)
\]

Thus, the answer is:

\[
\log_2 \left(\frac{11}{9}\right)
\]

If you have any questions or need further details, let me know! Here are some related questions you might consider:

1. What is the value of \( \frac{11}{9} \) as a decimal?
2. How can logarithmic properties be applied to simplify more complex expressions?
3. What is the change of base formula for logarithms?
4. How do you evaluate logarithms using a calculator?
5. Can you explain the significance of logarithms in real-world applications?

**Tip:** Remember that logarithms can help solve exponential equations, especially when you need to isolate a variable.

Discover the solution to log2 11 - log2 9 using logarithmic properties. This explanation demonstrates how to simplify the expression to log2 (11/9), providing a clear understanding of logarithmic concepts. Suitable for students in Grades 9-11.

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