To solve the expression $\log_2 11 - \log_2 9$, we can use the property of logarithms that states:

$\log_a b - \log_a c = \log_a \left(\frac{b}{c}\right)$

Applying this property, we have:

$\log_2 11 - \log_2 9 = \log_2 \left(\frac{11}{9}\right)$

Thus, the answer is:

$\log_2 \left(\frac{11}{9}\right)$

If you have any questions or need further details, let me know! Here are some related questions you might consider:

1. What is the value of $\frac{11}{9}$ as a decimal?
2. How can logarithmic properties be applied to simplify more complex expressions?
3. What is the change of base formula for logarithms?
4. How do you evaluate logarithms using a calculator?
5. Can you explain the significance of logarithms in real-world applications?

Tip: Remember that logarithms can help solve exponential equations, especially when you need to isolate a variable.