Math Problem Statement

(Related to Checkpoint​ 6.1)  ​(Loan amortization)  On December​ 31, Beth Klemkosky bought a yacht for

​$60 comma 00060,000.

She paid

​$12 comma 00012,000

down and agreed to pay the balance in

1313

equal annual installments that include both the principal and

88

percent interest on the declining balance. How big will the annual payments​ be?

Question content area bottom

Part 1

a.  On December​ 31, Beth Klemkosky bought a yacht for

​$60 comma 00060,000

and paid

​$12 comma 00012,000

​down, how much does she need to borrow to purchase the​ yacht?

​$48,00048,000  

​(Round to the nearest​ dollar.)

Part 2

b. If Beth agrees to pay the loan plus

88

percent compound interest on the unpaid balance over the next

1313

years in

1313

equal​ end-of-year payments, what will those equal payments​ be?

​$enter your response here  

​(Round to the nearest​ cent.)

Solution

Part 1:

a. Beth Klemkosky purchased a yacht for $60,000 and made a down payment of $12,000. The amount she needs to borrow is:

Amount to borrow=Total price of yachtDown payment\text{Amount to borrow} = \text{Total price of yacht} - \text{Down payment}

Amount to borrow=60,00012,000=48,000\text{Amount to borrow} = 60,000 - 12,000 = 48,000

So, the amount Beth needs to borrow is $48,000.


Part 2:

b. To find Beth's equal annual payments, we will use the formula for loan amortization with equal payments, where the payments cover both the principal and interest. The formula for the payment is:

P=rPV1(1+r)nP = \frac{r \cdot PV}{1 - (1 + r)^{-n}}

Where:

  • PP = the annual payment
  • rr = annual interest rate (in decimal form, so 8% becomes 0.08)
  • PVPV = present value of the loan (the amount borrowed, $48,000)
  • nn = number of periods (in this case, 13 years)

Step-by-step calculation:

  1. Interest rate: r=8%=0.08r = 8\% = 0.08
  2. Loan amount (Present value, PVPV) = $48,000
  3. Number of payments (years), n=13n = 13

Substitute these values into the amortization formula:

P=0.0848,0001(1+0.08)13P = \frac{0.08 \cdot 48,000}{1 - (1 + 0.08)^{-13}}

First, calculate the denominator:

1+0.08=1.081 + 0.08 = 1.08

1.08130.34951.08^{-13} \approx 0.3495

Now, subtract that value from 1:

10.3495=0.65051 - 0.3495 = 0.6505

Now, calculate the payment PP:

P=0.0848,0000.6505P = \frac{0.08 \cdot 48,000}{0.6505}

P=3,8400.65055,902.81P = \frac{3,840}{0.6505} \approx 5,902.81

So, the annual payment Beth needs to make is approximately $5,902.81.


Final Answers:

a. Amount to borrow: $48,000

b. Annual payment: $5,902.81


Would you like further details or have any other questions?


Here are 5 related questions to expand on this:

  1. How is the interest portion of each payment calculated over time in an amortization schedule?
  2. What is the total interest paid over the life of the loan?
  3. How much of the principal is repaid by the end of the 5th year?
  4. How would the payments change if the interest rate were 6% instead of 8%?
  5. How does the loan amortization process differ for monthly payments instead of annual payments?

Tip: The earlier payments in an amortized loan are more heavily weighted towards paying off interest, while later payments focus more on reducing the principal.

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Math Problem Analysis

Mathematical Concepts

Loan Amortization
Compound Interest
Algebra

Formulas

Amortization Payment Formula: P = (r * PV) / (1 - (1 + r)^(-n))
Compound Interest Formula: A = P(1 + r)^n

Theorems

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Suitable Grade Level

Grades 11-12, College Level