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From the graph, we can observe that the depth of water (in cm) increases linearly over time (in minutes). Let's first determine the rate at which the depth of water increases per minute.

By observing the graph:
- At \( t = 0 \) minutes, the depth is 0 cm.
- At \( t = 50 \) minutes, the depth is 200 cm.

This gives us a slope (rate of change) as:
\[
\text{slope} = \frac{\text{change in depth}}{\text{change in time}} = \frac{200 \, \text{cm} - 0 \, \text{cm}}{50 \, \text{min} - 0 \, \text{min}} = \frac{200}{50} = 4 \, \text{cm/min}.
\]

Now, to find the depth at \( t = 80 \) minutes:
\[
\text{depth} = \text{slope} \times \text{time} = 4 \, \text{cm/min} \times 80 \, \text{min} = 320 \, \text{cm}.
\]

Therefore, the depth of the water after 80 minutes will be **320 cm**.

Would you like more details or have any questions?

Here are five related questions:
1. How would the depth change if the rate of water addition was 6 cm/min instead of 4 cm/min?
2. What would the time be for the depth to reach 500 cm?
3. How can you express this linear relationship as an equation?
4. If the water was draining at 3 cm/min, how long would it take for the tank to empty from a depth of 200 cm?
5. Can you calculate the depth after 100 minutes?

**Tip:** When working with graphs, always identify key points to calculate the slope or rate of change for future predictions.

The graph below shows the depth of the water in an aquarium as water is added. If the graph continues in the same way, what will the depth of the water in the aquarium be after 80 minutes? Give your answer in cm.

This problem involves calculating the depth of water in an aquarium after 80 minutes by analyzing a linear graph. The graph shows a constant rate of change, with water depth increasing at 4 cm per minute. Learn how to solve this step-by-step for students in Grades 6-8.

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