It looks like you have a linear function, \( y = 5x \), and you want to evaluate it or understand its behavior over the interval from \( x = 0 \) to \( x = 2 \).

### Explanation
1. **Function**: The equation \( y = 5x \) represents a straight line passing through the origin with a slope of 5. This means for every unit increase in \( x \), \( y \) increases by 5 units.
  
2. **Interval**: You want to analyze the function for \( x \) values from 0 to 2. This means we are only looking at \( x \) values between (and including) 0 and 2.

3. **Calculations**:
   - When \( x = 0 \), \( y = 5(0) = 0 \).
   - When \( x = 1 \), \( y = 5(1) = 5 \).
   - When \( x = 2 \), \( y = 5(2) = 10 \).

4. **Graphical Interpretation**: Plotting these points on a graph will give a straight line segment starting from \( (0, 0) \) and ending at \( (2, 10) \).

### Additional Analysis
If you want to find more properties like the area under the curve from \( x = 0 \) to \( x = 2 \) or any other particular attribute, I can assist with that as well.

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Would you like more details on this function? Here are some related questions that you might find interesting:

1. What is the slope and y-intercept of the function \( y = 5x \)?
2. How do you calculate the area under \( y = 5x \) from \( x = 0 \) to \( x = 2 \)?
3. What would be the result of shifting the line \( y = 5x \) by 3 units up?
4. How do we find the derivative and integral of \( y = 5x \)?
5. What are the values of \( y \) at \( x = 0.5, 1.5 \), and \( 2.5 \)?

**Tip**: Always check the interval and domain of your function before analyzing it further. This will ensure you are focusing on the correct portion of the graph or values.

Explore the linear function y = 5x, and understand how it behaves over the interval from x = 0 to x = 2. Learn the step-by-step calculations, graphing techniques, and key concepts such as slope and intercept. Suitable for Grades 6-8 students.

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