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The function \( g(x) = x + 2 \) is given, and we need to complete the function table by calculating \( g(x) \) for each value of \( x \).

Let's compute \( g(x) \) for each value:

- For \( x = -5 \), \( g(-5) = -5 + 2 = -3 \)
- For \( x = -1 \), \( g(-1) = -1 + 2 = 1 \)
- For \( x = 0 \), \( g(0) = 0 + 2 = 2 \)
- For \( x = 1 \), \( g(1) = 1 + 2 = 3 \)
- For \( x = 2 \), \( g(2) = 2 + 2 = 4 \)

Thus, the completed table is:

\[
\begin{array}{|c|c|}
\hline
x & g(x) \\
\hline
-5 & -3 \\
-1 & 1 \\
0 & 2 \\
1 & 3 \\
2 & 4 \\
\hline
\end{array}
\]

Would you like more details or have any questions?

Here are five related questions to expand this topic:
1. What happens to \( g(x) \) when \( x \) increases by 1?
2. How would the function table look if the function was \( g(x) = x - 3 \)?
3. How would the graph of \( g(x) = x + 2 \) look like?
4. What is the domain and range of this linear function?
5. How does the slope of \( g(x) = x + 2 \) influence its growth?

**Tip**: When working with linear functions, the constant term shifts the graph vertically, while the coefficient of \( x \) determines the slope or steepness.

Complete the function table for the function g(x) = x + 2.

Learn how to complete a function table for the linear function g(x) = x + 2. This exercise focuses on basic algebraic concepts and is suitable for students in Grades 6-8.

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