**Write a function f(m) that models James’ daily profit.**

**For sale: $5 per melon**

**Cost to do business: $125 in rent** 

**Function:**

To model James' daily profit, we need to define a function that accounts for both his revenue and expenses.

### Problem Breakdown:
- **Revenue**: James earns $5 per melon sold.
- **Expenses**: He has a fixed cost of $125 (business rent).

### Variables:
Let:
- $ m $ represent the number of melons sold in a day.

### Function Definition:
- **Revenue** from selling $ m $ melons: $ 5m $
- **Total Expenses** (fixed rent): $125

### Profit Equation:
The daily profit, $ f(m) $, is the total revenue minus the total expenses:
\[
f(m) = 5m - 125
\]

So, the function that models James’ daily profit is:

\[
f(m) = 5m - 125
\]

This function shows that the profit depends on the number of melons sold. If $ m $ is large enough, James will make a profit. If $ m $ is too small, his profit will be negative (indicating a loss).

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Would you like further details or clarifications?

Here are 5 related questions:
1. What is the minimum number of melons James needs to sell to break even?
2. How much profit does James make if he sells 50 melons?
3. What happens to the profit if the cost of rent increases?
4. How would the function change if the price per melon increases?
5. What is the profit for selling 0 melons?

**Tip:** In functions like these, the slope (here 5) represents the profit per unit sold (per melon), while the constant (-125) represents fixed costs.

Write a function f(m) that models James’ daily profit. For sale: $5 per melon. Cost to do business: $125 in rent.

Learn how to model James' daily profit using a linear equation where each melon sold adds $5 in revenue, and his business incurs $125 in rent daily. This problem introduces key algebraic concepts in linear functions and is suitable for students in Grades 6-8.

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