The cost of renting a car is $55/wk plus $0.25/mi traveled during that week. An equation to represent the cost would be 
y = 55 + 0.25x,
 where x is the number of miles traveled.

Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?

We are given the equation representing the cost of renting a car as:

\[
y = 55 + 0.25x
\]

where $y$ is the total cost, and $x$ is the number of miles traveled. You have a maximum budget of $100, so we set $y = 100$ and solve for $x$:

\[
100 = 55 + 0.25x
\]

To find $x$, follow these steps:

1. Subtract 55 from both sides:

\[
100 - 55 = 0.25x
\]

\[
45 = 0.25x
\]

2. Divide both sides by 0.25:

\[
x = \frac{45}{0.25}
\]

\[
x = 180
\]

So, the maximum number of miles you could travel is **180 miles**.

Would you like more details on any step, or have further questions?

Here are five related questions:
1. What if your budget increased to $120? How would that affect the miles you could travel?
2. How would the formula change if the weekly cost was $60 instead of $55?
3. What happens if the per-mile cost increases to $0.30?
4. How would the total cost change if you traveled 200 miles?
5. Can you rearrange the equation to solve for $x$ in terms of $y$?

**Tip:** When solving equations, always isolate the variable step-by-step for clarity.

The cost of renting a car is $55/wk plus $0.25/mi traveled during that week. An equation to represent the cost would be y = 55 + 0.25x, where x is the number of miles traveled. Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?

Learn how to solve a linear equation to calculate the maximum number of miles you can travel with a $100 budget for car rental, where the cost is $55 per week plus $0.25 per mile. This problem covers key algebraic concepts and is suitable for students in Grades 6-8.

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