This is 10th grade math, Select the correct answer.
How many solutions exist for 2x + 1/ = 5?
O A. 0
• В. 1
0 с. 2
• D. 3

To determine how many solutions exist for the equation \( 2x + 1 = 5 \), let's solve it step by step:

1. Start with the given equation:
   \[
   2x + 1 = 5
   \]
   
2. Subtract 1 from both sides to isolate the \(2x\) term:
   \[
   2x = 5 - 1
   \]
   \[
   2x = 4
   \]

3. Divide both sides by 2 to solve for \(x\):
   \[
   x = \frac{4}{2} = 2
   \]

Thus, there is **1 solution** for this equation: \( x = 2 \).

The correct answer is:
- **B. 1**

Would you like further details or have any questions?

Here are 5 related questions:
1. How do you solve linear equations with variables on both sides?
2. What is the graphical interpretation of solving \( 2x + 1 = 5 \)?
3. How can you check your solution to a linear equation?
4. What is the difference between a unique solution and no solution in a linear equation?
5. Can an equation have more than one solution? If so, under what conditions?

**Tip**: Always isolate the variable step by step to avoid mistakes when solving equations.

How many solutions exist for 2x + 1 = 5?
O A. 0
O B. 1
O C. 2
O D. 3

Find out how many solutions exist for the linear equation 2x + 1 = 5 with a clear, step-by-step solution. This problem helps students understand basic algebra and linear equations, suitable for Grade 10 students.

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