Through (8,10) with m=-2/3 in point-slope form
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To write the equation of a line in point-slope form, we use the formula:

\[
y - y_1 = m(x - x_1)
\]

where:
- \((x_1, y_1)\) is a point on the line (in this case, (8, 10)),
- \(m\) is the slope (in this case, \(-\frac{2}{3}\)).

Substituting the given values into the formula:

\[
y - 10 = -\frac{2}{3}(x - 8)
\]

This is the equation of the line in point-slope form.

Would you like to expand or simplify this equation, or do you have any other questions?

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Here are 5 related questions:
1. How would you convert this equation into slope-intercept form?
2. What is the y-intercept of this line?
3. How would the equation change if the slope were positive \(\frac{2}{3}\)?
4. What is the distance between the point (8,10) and the x-axis?
5. Can you find another point that lies on this line?

**Tip:** Always double-check that the point you are using satisfies the equation after substitution!

Through (8,10) with m=-2/3 in point-slope form

Learn how to write the equation of a line through the point (8, 10) with a slope of -2/3 in point-slope form. This problem covers core algebraic concepts and the use of the point-slope formula, suitable for students in Grades 8-10.

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