Math Problem Statement

For the function g whose graph is given, state the following. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.)

(a)lim x → ∞ (g(x))

(b)lim x → -∞ (g(x))

(c)lim x → 0 (g(x))

(d)lim x → 2- (g(x))

(e)lim x → 2+ (g(x))

f)The equations of the asymptotes (Enter your answers as comma-separated lists.)

x=

y=

For the function g whose graph is given, state the following. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.) (a) lim x → ∞ (g(x)) (b) lim x → -∞ (g(x)) (c) lim x → 0 (g(x)) (d) lim x → 2- (g(x)) (e) lim x → 2+ (g(x)) (f) The equations of the asymptotes (Enter your answers as comma-separated lists.) x = y =

Solution

Let's analyze the limits and asymptotes based on the graph provided.

Solutions:

(a) limxg(x)\lim_{x \to \infty} g(x): As xx approaches infinity, the graph appears to level off at a particular value. Observing the graph, it seems to approach a horizontal asymptote around y=0y = 0, so: limxg(x)=0\lim_{x \to \infty} g(x) = 0

(b) limxg(x)\lim_{x \to -\infty} g(x): As xx approaches negative infinity, the graph oscillates but stabilizes near y=0y = 0. Thus: limxg(x)=0\lim_{x \to -\infty} g(x) = 0

(c) limx0g(x)\lim_{x \to 0} g(x): Looking closely at x=0x = 0, the graph does not show any significant oscillations or divergences around this point, so the function appears to approach a specific value. If the graph passes through y=1y = 1 at x=0x = 0, then: limx0g(x)=1\lim_{x \to 0} g(x) = 1

(d) limx2g(x)\lim_{x \to 2^-} g(x): As xx approaches 22 from the left, the graph heads towards positive infinity, indicating a vertical asymptote: limx2g(x)=\lim_{x \to 2^-} g(x) = \infty

(e) limx2+g(x)\lim_{x \to 2^+} g(x): As xx approaches 22 from the right, the graph goes towards negative infinity, reinforcing the presence of a vertical asymptote at x=2x = 2: limx2+g(x)=\lim_{x \to 2^+} g(x) = -\infty

(f) Equations of the asymptotes:

  • Vertical asymptote: Based on the behavior around x=2x = 2, there is a vertical asymptote at x=2x = 2.
  • Horizontal asymptote: As xx approaches both positive and negative infinity, yy approaches 0, so there is a horizontal asymptote at y=0y = 0.

Thus, the asymptote equations are: x=2,y=0x = 2, \quad y = 0


Would you like further details on any of these solutions?

Related Questions

  1. What is the significance of the horizontal asymptote in this function?
  2. How would the behavior change if the graph had an oscillating limit at infinity?
  3. Why does the function exhibit a vertical asymptote at x=2x = 2?
  4. How do horizontal asymptotes influence the end behavior of functions?
  5. Can you determine the continuity of g(x)g(x) based on the given limits?

Tip:

When analyzing a graph for asymptotes, always check both directions for horizontal asymptotes and both sides of points with potential vertical asymptotes to confirm the function’s behavior near those points.

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Math Problem Analysis

Mathematical Concepts

Limits
Asymptotes
End Behavior

Formulas

Limit notation: lim_{x→c} f(x)
Asymptote equations

Theorems

Limit laws
Definition of asymptotes

Suitable Grade Level

Grade 11-12