The expression provided is:

$\lim_{x \to 2} \sqrt{5x - 3}$

To solve this limit, we can directly substitute $x = 2$ into the expression since the function inside the square root is continuous for $x = 2$.

Substituting $x = 2$:

$\sqrt{5(2) - 3} = \sqrt{10 - 3} = \sqrt{7}$

Thus, the value of the limit is:

$\lim_{x \to 2} \sqrt{5x - 3} = \sqrt{7}$

Would you like more details or explanations on how limits of continuous functions work?

Here are 5 related questions to expand your understanding:

1. What is the general definition of a limit for a continuous function?
2. How do you solve limits for more complex functions, such as rational or trigonometric functions?
3. What happens if substitution into the limit results in an indeterminate form like $\frac{0}{0}$?
4. Can the square root function ever create discontinuities in limit problems?
5. How would the limit change if the function inside the square root had a negative value at $x = 2$?

Tip: When solving limits, always check if direct substitution works first, especially with continuous functions like polynomials and square roots.