The graph of $|f(x)| = |x - 5|$ shows an absolute value function, which creates a "V" shape. As $x$ approaches 5, the value of $|f(x)|$ approaches zero, because $|5 - 5| = 0$. This illustrates the limit $\lim_{x \to 5} |f(x)| = 0$.

Let me know if you need any further clarification, or if you want to explore specific details!

Here are five related questions for practice:

1. What is the limit of $|f(x)|$ as $x \to 5$ from the left and right?
2. How would the graph change if the function was $|x - 3|$ instead?
3. What is the derivative of $|x - 5|$ for $x \neq 5$?
4. Can you explain why the function is continuous at $x = 5$?
5. How does the absolute value affect the slope on either side of $x = 5$?

Tip: For absolute value functions, the slope changes at the point where the expression inside the absolute value equals zero!