To solve \( 180 \div 3 \) using long division:

1. **Step 1: Set up the problem.**  
   Write 180 under the division symbol and 3 outside.

   \[
   \begin{array}{r|l}
    3 & 180 \\
   \end{array}
   \]

2. **Step 2: Divide the first digit (1) by 3.**  
   Since 1 is smaller than 3, it cannot be divided. Consider the first two digits (18).

3. **Step 3: Divide 18 by 3.**  
   \[
   3 \text{ goes into } 18 \text{ exactly } 6 \text{ times.} 
   \]
   Write 6 above the 8.

   \[
   \begin{array}{r|l}
    3 & 18\underline{6}0 \\
   \end{array}
   \]

4. **Step 4: Multiply and subtract.**  
   Multiply 6 by 3 to get 18. Subtract 18 from 18 to get 0. Bring down the next digit (0).

   \[
   \begin{array}{r|l}
    3 & 180 \\
      & -18 \\
      & \underline{0}0 \\
   \end{array}
   \]

5. **Step 5: Divide the next digit.**  
   Divide 0 by 3, which gives 0. Write 0 next to the 6 above the line.

   \[
   \begin{array}{r|l}
    3 & 18\underline{60} \\
   \end{array}
   \]

   The final quotient is 60.

Thus, \( 180 \div 3 = 60 \).

Would you like more details or have any questions?

Here are five related questions to consider:
1. What is the long division process for dividing 360 by 6?
2. How do you check the result of a division problem?
3. What is the remainder when 182 is divided by 3?
4. How does long division work when the divisor is a larger number?
5. Can long division be used for dividing decimal numbers?

**Tip:** When performing long division, always start by dividing the leftmost digits and move right as you subtract and bring down the next digits.

Discover how to solve 180 divided by 3 using long division with this step-by-step guide. Includes detailed instructions and illustrations. Suitable for students in Grades 4-6.

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