Math Problem Statement

On réalise le montage électrique ci-contre. Une fois le condensateur est totalement chargé, on bascule l'interrupteur K en position ② à un instant t = 0. La courbe ci-contre représente la variation de la charge du condensateur en fonction du temps. 1. Déterminer l'équation différentielle vérifiée par la charge q(t). 2. Quel est le régime des oscillations. 3. Déterminer la pseudo-période T. 4. On suppose que la résistance du circuit est petite et n'a aucune influence sur les oscillations. Calculer la valeur de L. 5. Calculer l'énergie dissipée par l'effet joule entre les instants t1 = 0,006s et t2 = 0,03s. On donne C = 1µF.

Solution

The exercise involves an electrical circuit with a capacitor CC, an inductor LL, and a resistor rr. The setup indicates a situation where the capacitor is charged and an interrupt switch (K) is activated to begin oscillations, leading to a variation in the capacitor's charge over time.

Let's break down the tasks from the exercise:

  1. Determine the differential equation verified by the charge q(t)q(t):

    • Based on the circuit, we can expect this to involve an LC circuit with a capacitor, inductor, and potentially a resistor. The oscillatory nature indicates a second-order linear differential equation, commonly written as: Ld2qdt2+rdqdt+qC=0L \frac{d^2q}{dt^2} + r \frac{dq}{dt} + \frac{q}{C} = 0 The resistive term (due to rr) is small, so it might be negligible in the case you're analyzing.
  2. Identify the regime of oscillations:

    • Based on the oscillatory nature of q(t)q(t), it appears this could be an underdamped regime, where oscillations are present but slowly decay over time.
  3. Determine the pseudo-period TT:

    • The pseudo-period is the period of the oscillation, which can be found using the graph provided. It corresponds to the time between two peaks of the oscillation.
  4. Calculate the energy dissipated by Joule effect between the instants t1=0.006st_1 = 0.006 \, s and t2=0.03st_2 = 0.03 \, s:

    • Energy dissipated can be calculated from the power dissipated in the resistor P=rI2P = r I^2, where II is the current. However, for simplification, the graph and the small resistance assumption may allow for approximations.

Do you want help working through each of these parts step by step, or do you have specific questions on a particular one? Let me know!

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Oscillations
LC Circuit Analysis
Energy Dissipation

Formulas

L d²q/dt² + r dq/dt + q/C = 0
Pseudo-period T = Time between two peaks of oscillation
Energy dissipated by Joule effect: P = r I²

Theorems

Second-order linear differential equations
Energy conservation in oscillatory systems

Suitable Grade Level

Grades 11-12