Math Problem Statement

A periodic function of period \( \frac{2\pi}{\omega} \) is defined by: \[ f(t) = \begin{cases} E \sin(\omega t), & 0 \leq t < \frac{\pi}{\omega} \\ 0, & \frac{\pi}{\omega} \leq t < \frac{2\pi}{\omega} \end{cases} \] where \( E \) and \( \omega \) are positive constants. Show that the Laplace transform of \( f(t) \) is given by: \[ L\{ f(t) \} = \frac{E \omega}{(s^2 + \omega^2)} (1 - e^{-\frac{\pi s}{\omega}}) \]

Solution

The image you uploaded contains a mathematical problem involving a periodic function. It is asking to show the Laplace transform of the given periodic function, which is defined in piecewise form.

Here’s what the problem presents:

A periodic function f(t)f(t) is defined as:

\begin{cases} E \sin(\omega t), & 0 \leq t < \frac{\pi}{\omega} \\ 0, & \frac{\pi}{\omega} \leq t < \frac{2\pi}{\omega} \end{cases}$$ Where $$E$$ and $$\omega$$ are positive constants. The problem asks to show the Laplace transform of $$f(t)$$, which is $$L\{ f(t) \}$$. Would you like me to explain how to solve the Laplace transform for this function?

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Laplace Transform
Periodic Functions
Piecewise Functions

Formulas

Laplace Transform: \( L\{ f(t) \} = \int_0^\infty f(t)e^{-st} dt \)
Laplace Transform of Sine Function: \( L\{ \sin(\omega t) \} = \frac{\omega}{s^2 + \omega^2} \)
Periodic Function Property in Laplace Transform

Theorems

Laplace Transform Theorem
Shifting Theorem
Periodic Function Theorem

Suitable Grade Level

Undergraduate (Engineering, Mathematics, Physics)