https://file.aiquickdraw.com/mathbot/file/1727284896383yni52k46.jpg

Let's analyze the problem and form an equation.

### Problem Breakdown:
- Total amount raised by the lacrosse team: \$1775.50.
- Cost to rent the bus: \$901.50.
- Cost per player for meals: \$46 per player.
- The goal is to find the number of players $ x $ that can attend the tournament.

### Step 1: Set up the equation
The total cost for the team includes the bus rental and the meals for all players. Therefore, the total cost is:
\[
\text{Total cost} = 901.50 + 46x
\]
where $ x $ is the number of players.

Since the team has raised \$1775.50, we set this equal to the total cost:
\[
1775.50 = 901.50 + 46x
\]

### Step 2: Solve for $ x $
Now, solve the equation for $ x $.

\[
1775.50 - 901.50 = 46x
\]
\[
874 = 46x
\]
\[
x = \frac{874}{46}
\]
\[
x \approx 19
\]

### Conclusion:
The team can bring approximately 19 players to the tournament.

Do you want further details or have any questions? 

Here are some related questions for further practice:
1. If the bus rental cost increases by \$100, how many players can still attend?
2. If the team raises \$2000 instead, how many players can they bring?
3. What if each player's meal budget increases to \$50, how many players can now attend?
4. If 25 players are planning to go, how much more money does the team need to raise?
5. What would happen if the team finds a cheaper bus that costs only \$800?

**Tip**: Always ensure that both fixed and variable costs are accounted for when solving real-life budget-related problems.

Members of a lacrosse team raised $1775.50 to go to a tournament. They rented a bus for $901.50 and budgeted $46 per player for meals. Write and solve an equation which can be used to determine x, the number of players the team can bring to the tournament.

Learn how to solve a linear equation involving a budget problem for a lacrosse team. The team raised $1775.50, rented a bus for $901.50, and budgeted $46 per player for meals. Find out how many players can attend the tournament with a step-by-step solution. Suitable for Grades 7-9.

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