A projectile of mass m = 0.2 kg and initial speed vi = 200 m/s hits a stationary target of mass M = 2 kg and gets imbedded in it. The change in kinetic energy ΔE during this collision is closest to

In this problem, we have an inelastic collision, where a projectile of mass \( m = 0.2 \, \text{kg} \) hits a stationary target of mass \( M = 2 \, \text{kg} \), and they move together after the collision. The goal is to calculate the change in kinetic energy \( \Delta E \) during the collision.

### Step 1: Initial kinetic energy of the projectile
The initial kinetic energy \( E_i \) of the projectile is given by:

\[
E_i = \frac{1}{2} m v_i^2
\]

Substituting the given values:

\[
E_i = \frac{1}{2} \times 0.2 \, \text{kg} \times (200 \, \text{m/s})^2
\]

\[
E_i = 0.1 \times 40,000 = 4,000 \, \text{J}
\]

### Step 2: Final velocity after the collision
Since the projectile gets embedded in the target, the system (projectile + target) moves together after the collision. To find the final velocity \( v_f \), we use the conservation of momentum:

\[
m v_i = (m + M) v_f
\]

Solving for \( v_f \):

\[
v_f = \frac{m v_i}{m + M} = \frac{0.2 \times 200}{0.2 + 2} = \frac{40}{2.2} \approx 18.18 \, \text{m/s}
\]

### Step 3: Final kinetic energy of the system
The final kinetic energy \( E_f \) of the combined system (projectile + target) is:

\[
E_f = \frac{1}{2} (m + M) v_f^2
\]

Substituting the values:

\[
E_f = \frac{1}{2} \times (0.2 + 2) \times (18.18)^2
\]

\[
E_f = \frac{1}{2} \times 2.2 \times 330.6 \approx 363.66 \, \text{J}
\]

### Step 4: Change in kinetic energy
The change in kinetic energy \( \Delta E \) is:

\[
\Delta E = E_i - E_f = 4,000 - 363.66 \approx 3,636.34 \, \text{J}
\]

### Conclusion:
The change in kinetic energy during the collision is approximately \( \Delta E \approx 3,636 \, \text{J} \).

---

Would you like further details or have any questions on this? Here are some related questions for further understanding:

1. How does the principle of conservation of momentum apply to inelastic collisions?
2. What factors cause kinetic energy to decrease in inelastic collisions?
3. Can you calculate the velocity of the target after the collision for different values of initial speed?
4. How would the result change if the masses of the projectile and target were reversed?
5. What is the difference in energy conservation between elastic and inelastic collisions?

**Tip:** In inelastic collisions, while momentum is always conserved, kinetic energy is not fully conserved due to energy transformation into other forms like heat and sound.

A projectile of mass m = 0.2 kg and initial speed vi = 200 m/s hits a stationary target of mass M = 2 kg and gets embedded in it. The change in kinetic energy ΔE during this collision is closest to?

This detailed solution explains how to calculate the change in kinetic energy during an inelastic collision where a projectile of 0.2 kg embeds into a stationary 2 kg target. Key physics concepts such as conservation of momentum and kinetic energy are discussed. Suitable for high school physics students (Grades 10-12).

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