Math Problem Statement

what are the points on cos(x) graph in between 0 and 2π\pi

Solution

The cosine function, cos(x)\cos(x), is periodic with a period of 2π2\pi and it oscillates between -1 and 1. Here are some key points on the graph of cos(x)\cos(x) between 00 and 2π2\pi:

  1. x=0x = 0: cos(0)=1\cos(0) = 1.
  2. x=π2x = \frac{\pi}{2}: cos(π2)=0\cos\left(\frac{\pi}{2}\right) = 0.
  3. x=πx = \pi: cos(π)=1\cos(\pi) = -1.
  4. x=3π2x = \frac{3\pi}{2}: cos(3π2)=0\cos\left(\frac{3\pi}{2}\right) = 0.
  5. x=2πx = 2\pi: cos(2π)=1\cos(2\pi) = 1.

These points are critical values where the function changes its direction or reaches its maximum/minimum values.

Relative Questions:

  1. What is the period of the cos(x)\cos(x) function?
  2. How do you find the amplitude of cos(x)\cos(x)?
  3. What is the general formula for the maximum and minimum values of cos(x)\cos(x)?
  4. How does the graph of cos(x)\cos(x) compare to sin(x)\sin(x)?
  5. What are the intercepts of the cos(x)\cos(x) graph?

Tip: Remember, the cos(x)\cos(x) function is an even function, meaning cos(x)=cos(x)\cos(-x) = \cos(x), which reflects its symmetry about the y-axis.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Periodic Functions
Graphing

Formulas

cos(x) = adjacent/hypotenuse
cos(x) periodic function with period 2π

Theorems

Cosine Function Symmetry (cos(-x) = cos(x))
Key Points on the Unit Circle

Suitable Grade Level

Grades 9-11