Math Problem Statement
Solution
To calculate Karl Pearson's coefficient of correlation () between advertising expenditure and sales from the data provided in the image, we will follow these steps:
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Tabulate Data:
- List the values of (Advertising Expenditure) and (Sales).
- Compute the mean of () and ().
- Calculate , , , , and .
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Formula for Correlation Coefficient:
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Plug in values and solve.
Let me compute the values for you. numpy as np
Given data
advertising_expenditure = np.array([12, 15, 18, 23, 24, 38, 42, 48]) # in '000 Tk sales = np.array([5.0, 5.6, 5.8, 7.0, 7.2, 8.8, 9.2, 9.5]) # in Lakh Tk
Calculate means
mean_x = np.mean(advertising_expenditure) mean_y = np.mean(sales)
Calculate deviations from mean
x_deviation = advertising_expenditure - mean_x y_deviation = sales - mean_y
Calculate squares and product of deviations
x_deviation_squared = x_deviation2 y_deviation_squared = y_deviation2 xy_deviation_product = x_deviation * y_deviation
Calculate sums
sum_x_deviation_squared = np.sum(x_deviation_squared) sum_y_deviation_squared = np.sum(y_deviation_squared) sum_xy_deviation_product = np.sum(xy_deviation_product)
Calculate correlation coefficient (r)
r = sum_xy_deviation_product / np.sqrt(sum_x_deviation_squared * sum_y_deviation_squared)
mean_x, mean_y, sum_x_deviation_squared, sum_y_deviation_squared, sum_xy_deviation_product, rThe calculations yield the following:
- Mean of advertising expenditure () = 27.5 ('000 Tk)
- Mean of sales () = 7.2625 (Lakh Tk)
- Sum of squared deviations for :
- Sum of squared deviations for :
- Sum of product of deviations:
Karl Pearson's coefficient of correlation () is:
This indicates a very strong positive correlation between advertising expenditure and sales.
Would you like me to provide detailed step-by-step calculations or further interpretation of the result?
5 Questions You May Want to Explore:
- How do we interpret a correlation coefficient near ?
- Can causation between advertising and sales be inferred from this correlation?
- What are the potential limitations of using Pearson's in this context?
- How would the result change if one of the data points was an outlier?
- What other statistical methods could be used to analyze this relationship?
Tip:
Remember, correlation does not imply causation. Even with a strong , external factors could influence sales.
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Math Problem Analysis
Mathematical Concepts
Statistics
Correlation Analysis
Data Deviation
Formulas
r = Σ((x - x̄)(y - ȳ)) / √(Σ(x - x̄)² × Σ(y - ȳ)²)
Theorems
Karl Pearson's Coefficient of Correlation
Suitable Grade Level
Undergraduate level, or advanced high school (Grades 11-12)
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