Math Problem Statement

Calculate Karl Pearson's coefficient of correlation between advertising expenditure and sales for the period 1995-2002 based on the provided data.

Solution

To calculate Karl Pearson's coefficient of correlation (rr) between advertising expenditure and sales from the data provided in the image, we will follow these steps:

  1. Tabulate Data:

    • List the values of xx (Advertising Expenditure) and yy (Sales).
    • Compute the mean of xx (xˉ\bar{x}) and yy (yˉ\bar{y}).
    • Calculate (xxˉ)(x - \bar{x}), (yyˉ)(y - \bar{y}), (xxˉ)2(x - \bar{x})^2, (yyˉ)2(y - \bar{y})^2, and (xxˉ)(yyˉ)(x - \bar{x})(y - \bar{y}).
  2. Formula for Correlation Coefficient: r=(xxˉ)(yyˉ)(xxˉ)2(yyˉ)2r = \frac{\sum{(x - \bar{x})(y - \bar{y})}}{\sqrt{\sum{(x - \bar{x})^2} \cdot \sum{(y - \bar{y})^2}}}

  3. Plug in values and solve.

Let me compute the values for you. numpy as np

Given data

advertising_expenditure = np.array([12, 15, 18, 23, 24, 38, 42, 48]) # in '000 Tk sales = np.array([5.0, 5.6, 5.8, 7.0, 7.2, 8.8, 9.2, 9.5]) # in Lakh Tk

Calculate means

mean_x = np.mean(advertising_expenditure) mean_y = np.mean(sales)

Calculate deviations from mean

x_deviation = advertising_expenditure - mean_x y_deviation = sales - mean_y

Calculate squares and product of deviations

x_deviation_squared = x_deviation2 y_deviation_squared = y_deviation2 xy_deviation_product = x_deviation * y_deviation

Calculate sums

sum_x_deviation_squared = np.sum(x_deviation_squared) sum_y_deviation_squared = np.sum(y_deviation_squared) sum_xy_deviation_product = np.sum(xy_deviation_product)

Calculate correlation coefficient (r)

r = sum_xy_deviation_product / np.sqrt(sum_x_deviation_squared * sum_y_deviation_squared)

mean_x, mean_y, sum_x_deviation_squared, sum_y_deviation_squared, sum_xy_deviation_product, rThe calculations yield the following:

  • Mean of advertising expenditure (xˉ\bar{x}) = 27.5 ('000 Tk)
  • Mean of sales (yˉ\bar{y}) = 7.2625 (Lakh Tk)
  • Sum of squared deviations for xx: (xxˉ)2=1260.0\sum{(x - \bar{x})^2} = 1260.0
  • Sum of squared deviations for yy: (yyˉ)2=21.21875\sum{(y - \bar{y})^2} = 21.21875
  • Sum of product of deviations: (xxˉ)(yyˉ)=161.25\sum{(x - \bar{x})(y - \bar{y})} = 161.25

Karl Pearson's coefficient of correlation (rr) is: r=0.9862r = 0.9862

This indicates a very strong positive correlation between advertising expenditure and sales.


Would you like me to provide detailed step-by-step calculations or further interpretation of the result?

5 Questions You May Want to Explore:

  1. How do we interpret a correlation coefficient near +1+1?
  2. Can causation between advertising and sales be inferred from this correlation?
  3. What are the potential limitations of using Pearson's rr in this context?
  4. How would the result change if one of the data points was an outlier?
  5. What other statistical methods could be used to analyze this relationship?

Tip:

Remember, correlation does not imply causation. Even with a strong rr, external factors could influence sales.

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Math Problem Analysis

Mathematical Concepts

Statistics
Correlation Analysis
Data Deviation

Formulas

r = Σ((x - x̄)(y - ȳ)) / √(Σ(x - x̄)² × Σ(y - ȳ)²)

Theorems

Karl Pearson's Coefficient of Correlation

Suitable Grade Level

Undergraduate level, or advanced high school (Grades 11-12)