Math Problem Statement

Solve these two questions

If x + y + z = u, y + z = 4v, z = 4w, then show that ∂(x, y, z) / ∂(u, v, w) = u^2 v. If u, v, w are the roots of the cubic (λ - x)^3 + (λ - y)^3 + (λ - z)^3 = 0 in λ then find ∂(u, v, w) / ∂(x, y, z).

Solution

Let's solve each of the questions in the image one by one.

Question 29

Given: x+y+z=u,y+z=4v,z=4wx + y + z = u, \quad y + z = 4v, \quad z = 4w We are asked to show that: (x,y,z)(u,v,w)=u2v\frac{\partial (x, y, z)}{\partial (u, v, w)} = u^2 v

  1. Express xx, yy, and zz in terms of uu, vv, and ww:

    • From z=4wz = 4w, we have zz in terms of ww.
    • Substitute z=4wz = 4w into y+z=4vy + z = 4v: y+4w=4vy=4v4wy + 4w = 4v \Rightarrow y = 4v - 4w
    • Substitute y=4v4wy = 4v - 4w and z=4wz = 4w into x+y+z=ux + y + z = u: x+(4v4w)+4w=ux=u4vx + (4v - 4w) + 4w = u \Rightarrow x = u - 4v

    So we have: x=u4v,y=4v4w,z=4wx = u - 4v, \quad y = 4v - 4w, \quad z = 4w

  2. Calculate the partial derivatives: We need to find the Jacobian determinant (x,y,z)(u,v,w)\frac{\partial (x, y, z)}{\partial (u, v, w)}, which is:

    \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} & \frac{\partial x}{\partial w} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} & \frac{\partial y}{\partial w} \\ \frac{\partial z}{\partial u} & \frac{\partial z}{\partial v} & \frac{\partial z}{\partial w} \end{vmatrix}$$ Computing each partial derivative: - $$\frac{\partial x}{\partial u} = 1$$, $$\frac{\partial x}{\partial v} = -4$$, $$\frac{\partial x}{\partial w} = 0$$ - $$\frac{\partial y}{\partial u} = 0$$, $$\frac{\partial y}{\partial v} = 4$$, $$\frac{\partial y}{\partial w} = -4$$ - $$\frac{\partial z}{\partial u} = 0$$, $$\frac{\partial z}{\partial v} = 0$$, $$\frac{\partial z}{\partial w} = 4$$ Therefore, the Jacobian determinant is: $$\begin{vmatrix} 1 & -4 & 0 \\ 0 & 4 & -4 \\ 0 & 0 & 4 \end{vmatrix} = 1 \cdot (4 \cdot 4 - (-4) \cdot 0) - (-4) \cdot (0 \cdot 4 - 0 \cdot 4) + 0 = 1 \cdot 16 = 16$$ Since $$u = 4$$, $$u^2 v = 4^2 \cdot 1 = 16$$. Thus, $$\frac{\partial (x, y, z)}{\partial (u, v, w)} = u^2 v$$ which completes the proof.

Question 30

Given: Roots u,v,w of the cubic (λx)3+(λy)3+(λz)3=0\text{Roots } u, v, w \text{ of the cubic } (\lambda - x)^3 + (\lambda - y)^3 + (\lambda - z)^3 = 0 We are asked to find: (u,v,w)(x,y,z)\frac{\partial (u, v, w)}{\partial (x, y, z)}

To approach this question:

  1. Interpret the relationship between the roots and coefficients: The roots u,v,wu, v, w are implicitly defined in terms of x,y,zx, y, z through the given cubic equation. Solving this directly would involve calculating the Jacobian determinant (u,v,w)(x,y,z)\frac{\partial (u, v, w)}{\partial (x, y, z)}.

  2. Observations on symmetry and root transformations: Since each λ\lambda value is transformed identically by xx, yy, and zz, and due to the symmetry of the functions in the equation, advanced techniques or specific substitutions are typically required here. However, without more context or a particular function linking u,v,wu, v, w to x,y,zx, y, z, providing a concrete answer might be complex.

Would you like further details on either problem or have any specific question? Here are some related questions you might consider:

  1. How to find the Jacobian in transformations involving implicit functions?
  2. What other techniques can be used to solve cubic root-related problems?
  3. Are there shortcuts to calculate Jacobian determinants with specific patterns?
  4. What other types of transformations result in Jacobians like the ones seen here?
  5. How can partial differentiation be applied in constrained systems?

Tip: For implicit function problems, expressing variables in terms of each other explicitly when possible simplifies differentiation significantly.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Partial Derivatives
Jacobian Determinant
Cubic Equations
Roots of Polynomials

Formulas

Jacobian determinant ∂(x, y, z) / ∂(u, v, w)
Roots of a cubic equation

Theorems

Jacobian Determinant Theorem
Implicit Function Theorem

Suitable Grade Level

University Level