Math Problem Statement

In ∆QRS, if QR ≅ RS, m∠Q = 8x - 17, m∠R = 19x + 4, and m∠S = 5x + 1, find the value of x.

Solution

The problem in the image asks us to find the value of xx given the following information:

  • In QRS\triangle QRS, QRRS\overline{QR} \cong \overline{RS} (so the triangle is isosceles),
  • mQ=8x17m\angle Q = 8x - 17,
  • mR=19x+4m\angle R = 19x + 4,
  • mS=5x+1m\angle S = 5x + 1.

Since QRS\triangle QRS is isosceles, we know that the base angles are congruent. The base angles are Q\angle Q and S\angle S, so: mQ=mSm\angle Q = m\angle S Thus, we can set up the equation: 8x17=5x+18x - 17 = 5x + 1 Now, we solve for xx.

Step 1: Simplify the equation

8x5x=1+178x - 5x = 1 + 17 3x=183x = 18

Step 2: Solve for xx

x=183=6x = \frac{18}{3} = 6

So, the value of xx is 66.

Would you like more details on how to substitute this value back into the angles to check the solution?

Relative questions:

  1. What are the measures of the angles QQ, RR, and SS when x=6x = 6?
  2. How does the fact that the triangle is isosceles affect the solution process?
  3. Can you apply a similar method to other types of isosceles triangles?
  4. How do we know QRS\triangle QRS is an isosceles triangle?
  5. What happens if the given angles sum to more than 180 degrees?

Tip: Always check whether the given triangle is isosceles or equilateral because it can help you set up angle relationships easily!

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Isosceles Triangle

Formulas

Congruent base angles theorem
Algebraic equation solving

Theorems

Base Angles Theorem for Isosceles Triangles
Sum of Angles in a Triangle

Suitable Grade Level

Grades 8-10