Math Problem Statement
Solution
Let’s analyze the problem.
The problem describes an isosceles triangle with:
- Two equal sides.
- One side that is five times the length of the shorter side.
- A perimeter of at least 60 cm.
Let the length of the shorter side be . Then:
- Two equal sides each have length ,
- The third side is ,
- The perimeter is .
Step 1: Solve for
The perimeter condition says:
Thus, the minimum integer value of is cm.
Step 2: Verify the side lengths
- The shorter sides: ,
- The longer side: .
The sides satisfy the triangle inequality rule:
- is not true (the sides cannot form a triangle).
To satisfy the inequality, we need to increase .
Step 3: Adjust for triangle inequality
For the inequality , we simplify:
So, the minimum value of is .
Final Answer:
- The shorter sides are ,
- The longer side is .
The minimum side lengths are:
Let me know if you’d like further explanation or details! Here are 5 related questions:
- How does the triangle inequality rule work?
- Can we solve similar problems for different perimeters?
- What is the general approach to solving isosceles triangle problems?
- How can this problem be represented graphically?
- What are other real-world applications of the triangle inequality?
Tip: Always verify all constraints, especially the triangle inequality, when solving triangle-related problems!
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Algebra
Geometry
Triangle Inequality
Perimeter of Triangles
Formulas
Perimeter of a triangle: P = a + b + c
Triangle inequality: a + b > c
Theorems
Triangle Inequality Theorem
Suitable Grade Level
Grades 7-10
Related Recommendation
Isosceles Triangle Perimeter Problem: Find the Unequal Side Length
Solving Isosceles Triangle Perimeter Problem: Analyzing Triangle Inequality
Determine the Third Side of an Isosceles Triangle with Sides 7 cm and 5 cm
Finding the Perimeter of an Isosceles Triangle with Given Height
Find the Angle Bisector Length in an Isosceles Triangle with Base 5 and Side 20