Math Problem Statement
In a survey of 700 investors, it was reported that 440 had invested in stocks, 384 had invested in bonds, and 87 had not invested in either stocks or bonds.
Exercise (a) How many investors had invested in both stocks and bonds?
Part 1 of 3 Let S = {investors in stock} and B = {investors in bonds}.
Since there were a total of 700 investors and 87 of them had not invested in either stocks or bonds, the number investing in stocks or bonds is n(S ∪ B) = 700 − 87 Correct: Your answer is correct. seenKey 87
= 613 Correct: Your answer is correct. seenKey 613 . Part 2 of 3 It is stated in the problem that n(S) = 440 and n(B) = 384.
To find the number of investors who had invested in both stocks and bonds, use the Inclusion-Exclusion Principle, given as n(S ∪ B) = n(S) + n(B) − n(S ∩ B).
Substitute the given information and n(S ∪ B) = 613 into this formula. 613 = 440 +
Incorrect: Your answer is incorrect. − n(S ∩ B)
Solution
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Math Problem Analysis
Mathematical Concepts
Set Theory
Inclusion-Exclusion Principle
Algebra
Formulas
n(S ∪ B) = n(S) + n(B) − n(S ∩ B)
n(S ∪ B) = 613
n(S) = 440
n(B) = 384
n(S ∩ B) = 824 - 613
Theorems
Inclusion-Exclusion Principle
Suitable Grade Level
Grades 9-12
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