Math Problem Statement

The function f(x) = -log_2(-(x - 2)) - 2 is graphed below. Plot all lattice points of the inverse. Use the labeled points as your guide.

Solution

The function given is f(x)=log2((x2))2f(x) = -\log_2(-(x-2)) - 2, and you are asked to plot lattice points of the inverse and provide information about the inverse function, including asymptotes, range, and behavior.

Step 1: Find the inverse function

To find the inverse f1(x)f^{-1}(x), follow these steps:

  1. Set y=f(x)=log2((x2))2y = f(x) = -\log_2(-(x-2)) - 2.
  2. Solve for xx in terms of yy.

y=log2((x2))2y = -\log_2(-(x - 2)) - 2 Add 2 to both sides: y+2=log2((x2))y + 2 = -\log_2(-(x - 2)) Multiply both sides by -1: (y+2)=log2((x2))-(y + 2) = \log_2(-(x - 2)) Rewrite the equation in exponential form: 2(y+2)=(x2)2^{-(y + 2)} = -(x - 2) Now solve for xx: x2=2(y+2)x - 2 = -2^{-(y + 2)} x=22(y+2)x = 2 - 2^{-(y + 2)} Thus, the inverse function is: f1(x)=22(x+2)f^{-1}(x) = 2 - 2^{-(x + 2)}

Step 2: Identify asymptotes and behavior

  • Horizontal asymptote: The inverse function has a horizontal asymptote at y=2y = 2, because as xx \to \infty, 2(x+2)2^{-(x+2)} approaches 0.
  • Range of the inverse function: Since the original function f(x)f(x) has a range of (,2)(-\infty, -2), the inverse function f1(x)f^{-1}(x) will have a domain of (,2)(-\infty, -2) and a range of (,2)(-\infty, 2).
  • Behavior: The inverse is decreasing on its domain, as shown by the negative power of 2 in the inverse expression.

Step 3: Lattice points of the inverse

The inverse is a transformation of the original function, so you should plot points where the coordinates switch, reflecting across the line y=xy = x. For example, if the original function has a point (x1,y1)(x_1, y_1), the inverse function will have the point (y1,x1)(y_1, x_1).

Answer:

The inverse function is: f1(x)=22(x+2)f^{-1}(x) = 2 - 2^{-(x+2)}

  • It has a horizontal asymptote at y=2y = 2.
  • The range of the inverse function is (,2)(-\infty, 2), and it is decreasing on its domain (,2)(-\infty, -2).

Would you like further details or explanations?


Here are some follow-up questions to extend your understanding:

  1. How does the base of the logarithm affect the shape of the graph of f(x)f(x)?
  2. What would happen if the logarithmic function had a positive coefficient instead of negative?
  3. Can you find the derivative of f1(x)f^{-1}(x) using the inverse function rule?
  4. How do you identify lattice points for more complex inverses?
  5. How does the domain of f(x)f(x) change when shifting the function horizontally?

Tip: Always remember that the domain of the inverse function is the range of the original function and vice versa.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Logarithmic Functions
Graphing Transformations
Exponential Functions

Formulas

f(x) = -log_2(-(x - 2)) - 2
f^{-1}(x) = 2 - 2^{-(x + 2)}

Theorems

Inverse Function Theorem
Properties of Logarithms
Exponential and Logarithmic Relationship

Suitable Grade Level

Grades 10-12