Math Problem Statement

The function f(x) = x + 8 is one-to-one. a. Find an equation for f^(-1)(x), the inverse function. b. Verify that your equation is correct by showing that f(f^(-1)(x)) = x and f^(-1)(f(x)) = x.

Solution

To solve the problem step by step:


Part a: Find the inverse function

The original function is given as:
f(x)=x+8f(x) = x + 8
To find the inverse f1(x)f^{-1}(x):

  1. Replace f(x)f(x) with yy:
    y=x+8y = x + 8
  2. Swap xx and yy to solve for yy:
    x=y+8x = y + 8
  3. Solve for yy:
    y=x8y = x - 8 Thus, the inverse function is:
    f1(x)=x8f^{-1}(x) = x - 8

This matches choice C.


Part b: Verify the inverse function

To verify f(f1(x))=xf(f^{-1}(x)) = x and f1(f(x))=xf^{-1}(f(x)) = x:

  1. First verification f(f1(x))f(f^{-1}(x)):
    Substitute f1(x)=x8f^{-1}(x) = x - 8 into f(x)f(x):
    f(f1(x))=f(x8)=(x8)+8f(f^{-1}(x)) = f(x - 8) = (x - 8) + 8 Simplify:
    f(f1(x))=xf(f^{-1}(x)) = x

  2. Second verification f1(f(x))f^{-1}(f(x)):
    Substitute f(x)=x+8f(x) = x + 8 into f1(x)f^{-1}(x):
    f1(f(x))=f1(x+8)=(x+8)8f^{-1}(f(x)) = f^{-1}(x + 8) = (x + 8) - 8 Simplify:
    f1(f(x))=xf^{-1}(f(x)) = x

Both verifications are correct.


Final Answers:

  • Inverse Function: f1(x)=x8f^{-1}(x) = x - 8 (choice C).
  • Verification: f(f1(x))=xf(f^{-1}(x)) = x and f1(f(x))=xf^{-1}(f(x)) = x.

Do you need more clarification or further steps? Let me know!
Here are some related questions for practice:

  1. How do you verify an inverse function for a quadratic equation?
  2. What are the steps to find the inverse of f(x)=2x+3f(x) = 2x + 3?
  3. Can all functions have an inverse? Explain why or why not.
  4. What happens to the graph of a function when you find its inverse?
  5. How does the horizontal line test relate to the existence of an inverse function?

Tip: To find an inverse, swap xx and yy, then solve for yy.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Algebraic Manipulation

Formulas

f(f^(-1)(x)) = x
f^(-1)(f(x)) = x

Theorems

Definition of Inverse Functions

Suitable Grade Level

Grades 9-11