Math Problem Statement
Solution
Let's carefully solve each part of the question.
Given:
- on the interval .
- The derivatives provided are:
- .
Part (a): Where is increasing?
To determine where is increasing, we need to analyze where (the first derivative is positive).
From the given derivative:
Steps:
-
Factor : Since for all real , the sign of depends only on .
-
Solve : To solve this inequality, notice: The sign of determines where is positive.
- when within a -period.
Therefore:
-
Final Answer for Part (a): is increasing on the interval:
Part (b): Where is concave up?
To determine where is concave up, we analyze where (the second derivative is positive).
From the given second derivative:
Steps:
-
Factor : Since for all , the sign of depends only on .
-
Solve :
- when within the interval .
-
Final Answer for Part (b): is concave up on the interval:
Final Results:
- (a) is increasing on .
- (b) is concave up on .
Do you need further clarification or a detailed graph of these intervals?
Here are 5 related questions you might consider:
- How do you determine the intervals where is decreasing?
- What is the behavior of at the critical points?
- How do you graph and identify its key features?
- How can you use the first derivative test to confirm local maxima or minima?
- How is concavity related to the inflection points of ?
Tip: To determine where a function is increasing, always analyze the sign of the first derivative!
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Increasing and Decreasing Functions
Concavity
Formulas
First Derivative: f'(x) = e^x (sin x + cos x)
Second Derivative: f''(x) = 2e^x cos x
Theorems
A function is increasing when f'(x) > 0.
A function is concave up when f''(x) > 0.
Suitable Grade Level
Grades 11-12 (Advanced Calculus)
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