To express the given condition $11 > x$ or $25 \leq x$ in interval notation:

1. The inequality $11 > x$ translates to $x \in (-\infty, 11)$.
2. The inequality $25 \leq x$ translates to $x \in [25, \infty)$.
3. Since the condition uses "or", we take the union of these intervals.

Final Answer:
$(-\infty, 11) \cup [25, \infty)$

Would you like a detailed explanation of how to solve this or examples of similar problems?

Related Questions:

1. What is the difference between "and" and "or" in set notation?
2. How would you express $11 \leq x \leq 25$ in interval notation?
3. Can you solve an example with "and" instead of "or"?
4. How do you graph this inequality on a number line?
5. What happens if $11 = x$ is included in the first inequality?

Tip: Always check whether the inequalities involve inclusive ($\leq, \geq$) or exclusive ($<, >$) bounds when writing