Math Problem Statement

The circles with centers C1 and C2 have equal radii of length r cm. The line C1C2 is a radius of both circles. The two circles intersect at A and B. (a) Given that the perimeter of the shaded region is 4π cm, find the value of r. (b) Find the exact area of the shaded region.

Solution

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Problem Description:

  1. Two circles C1C_1 and C2C_2 with equal radii rr intersect at points AA and BB, forming a lens-shaped shaded region.
  2. The line segment C1C2C_1C_2 is the distance between the centers of the circles, and it's given that C1C2=rC_1C_2 = r.
  3. In part (a), we are told that the perimeter of the shaded region is 4πcm4\pi \, \text{cm}, and we are to find the radius rr.
  4. Part (b) asks us to calculate the exact area of the shaded region.

(a) Perimeter of the Shaded Region:

The shaded region's perimeter is composed of two circular arcs:

  1. Arc from AA to BB on C1C_1's circumference.
  2. Arc from AA to BB on C2C_2's circumference.

The total perimeter of the shaded region is 4πcm4\pi \, \text{cm}, and we know that:

  • Each arc is a semicircle because C1C2=rC_1C_2 = r. Thus, the two arcs together form a full circle.

The perimeter of one full circle is 2πr2\pi r. Setting this equal to the given total perimeter: 2πr=4π2\pi r = 4\pi Dividing through by 2π2\pi: r=2cmr = 2 \, \text{cm}


(b) Area of the Shaded Region:

The shaded region is the intersection of two circles. To find the area of this lens-shaped region, we subtract the area of the two triangular segments from the area of the overlapping circular segment.

  1. The two intersecting circles form two circular segments, each subtending an angle of π3\frac{\pi}{3} radians (60°) at the circle's center, since C1C2=rC_1C_2 = r and forms an equilateral triangle with radii.

  2. Area of one circular segment: Area of segment=12r2(θsinθ)\text{Area of segment} = \frac{1}{2} r^2 (\theta - \sin\theta) Here θ=π3\theta = \frac{\pi}{3}. Using r=2r = 2: Area of one segment=12(22)(π3sinπ3)\text{Area of one segment} = \frac{1}{2} (2^2) \left(\frac{\pi}{3} - \sin\frac{\pi}{3}\right) =2(π332)= 2 \left(\frac{\pi}{3} - \frac{\sqrt{3}}{2}\right)

  3. Total shaded area: The shaded region consists of two circular segments, so: Shaded area=2×Area of one segment\text{Shaded area} = 2 \times \text{Area of one segment} Shaded area=22(π332)\text{Shaded area} = 2 \cdot 2 \left(\frac{\pi}{3} - \frac{\sqrt{3}}{2}\right) Shaded area=4(π332)cm2\text{Shaded area} = 4\left(\frac{\pi}{3} - \frac{\sqrt{3}}{2}\right) \, \text{cm}^2


Final Answers:

(a) r=2cmr = 2 \, \text{cm}
(b) Exact Area=4(π332)cm2\text{Exact Area} = 4\left(\frac{\pi}{3} - \frac{\sqrt{3}}{2}\right) \, \text{cm}^2


Would you like me to explain any part further?
Here are some related questions for practice:

  1. How do you derive the formula for the area of a circular segment?
  2. If the distance between the circle centers were r/2r/2, how would the problem change?
  3. What is the geometric significance of the perimeter and area relationships?
  4. Can you find the total area of the two circles, including the non-shaded parts?
  5. What happens to the shaded region if the distance C1C2>rC_1C_2 > r?

Tip: Always visualize problems involving geometry and intersections to ensure clarity in the solution process!

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Math Problem Analysis

Mathematical Concepts

Geometry
Circle properties
Arc length
Area of circular segments

Formulas

Perimeter of a circle = 2πr
Area of circular segment = 1/2 r^2 (θ - sinθ)

Theorems

Basic properties of circles
Trigonometric relationships in a circle

Suitable Grade Level

Grades 10-12