Math Problem Statement

Determine the following integrals: 1) ∫ (2 / 3e^x) dx 2) ∫ (3x^2 - 5x) / x dx 3) ∫ (3 / 7√x^4) dx 4) ∫ ((2 + t)^2 / √t) dt

Solution

Let us solve the integrals step by step.


Problem 1:

23exdx\int \frac{2}{3e^x} \, dx

Simplify: 23exdx=23exdx\int \frac{2}{3} e^{-x} \, dx = \frac{2}{3} \int e^{-x} \, dx

The integral of exe^{-x} is ex-e^{-x}: 23(ex)+C=23ex+C\frac{2}{3} (-e^{-x}) + C = -\frac{2}{3} e^{-x} + C


Problem 2:

3x25xxdx\int \frac{3x^2 - 5x}{x} \, dx

Simplify the fraction: (3x5)dx\int \left( 3x - 5 \right) \, dx

Integrate each term: 3xdx5dx=3x225x+C\int 3x \, dx - \int 5 \, dx = \frac{3x^2}{2} - 5x + C


Problem 3:

37x45dx\int \frac{3}{7 \, \sqrt[5]{x^4}} \, dx

Rewrite x45=x4/5\sqrt[5]{x^4} = x^{4/5}: 37x4/5dx=37x4/5dx\int \frac{3}{7} x^{-4/5} \, dx = \frac{3}{7} \int x^{-4/5} \, dx

The integral of xnx^n is xn+1n+1\frac{x^{n+1}}{n+1}: 37x4/5+14/5+1=37x1/51/5=375x1/5=157x1/5+C\frac{3}{7} \cdot \frac{x^{-4/5 + 1}}{-4/5 + 1} = \frac{3}{7} \cdot \frac{x^{1/5}}{1/5} = \frac{3}{7} \cdot 5x^{1/5} = \frac{15}{7} x^{1/5} + C


Problem 4:

(2+t)2tdt\int \frac{(2 + t)^2}{\sqrt{t}} \, dt

Expand (2+t)2=4+4t+t2(2 + t)^2 = 4 + 4t + t^2: 4+4t+t2tdt=4tdt+4ttdt+t2tdt\int \frac{4 + 4t + t^2}{\sqrt{t}} \, dt = \int \frac{4}{\sqrt{t}} \, dt + \int \frac{4t}{\sqrt{t}} \, dt + \int \frac{t^2}{\sqrt{t}} \, dt

Simplify each term:

  1. 4tdt=4t1/2dt=42t1/2=8t\int \frac{4}{\sqrt{t}} \, dt = 4 \int t^{-1/2} \, dt = 4 \cdot 2t^{1/2} = 8\sqrt{t}
  2. 4ttdt=4t1/2dt=423t3/2=83t3/2\int \frac{4t}{\sqrt{t}} \, dt = 4 \int t^{1/2} \, dt = 4 \cdot \frac{2}{3} t^{3/2} = \frac{8}{3} t^{3/2}
  3. t2tdt=t3/2dt=25t5/2\int \frac{t^2}{\sqrt{t}} \, dt = \int t^{3/2} \, dt = \frac{2}{5} t^{5/2}

Combine: 8t+83t3/2+25t5/2+C8\sqrt{t} + \frac{8}{3} t^{3/2} + \frac{2}{5} t^{5/2} + C


Final Answers:

  1. 23ex+C-\frac{2}{3} e^{-x} + C
  2. 3x225x+C\frac{3x^2}{2} - 5x + C
  3. 157x1/5+C\frac{15}{7} x^{1/5} + C
  4. 8t+83t3/2+25t5/2+C8\sqrt{t} + \frac{8}{3} t^{3/2} + \frac{2}{5} t^{5/2} + C

Would you like detailed steps for any specific part?

5 Related Questions:

  1. What is the general formula for integrating exponential functions?
  2. How does simplifying the integrand help in solving complex integrals?
  3. Can the power rule for integration be applied to fractional exponents?
  4. How is the expansion of polynomials useful in integration?
  5. What are some common mistakes to avoid when integrating expressions?

Tip:

Always simplify the integrand before starting to integrate—it can save time and reduce the chance of errors!

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Simplification of Rational Expressions
Power Rule for Integration
Exponential Functions
Polynomial Expansion

Formulas

∫ e^(-x) dx = -e^(-x) + C
∫ x^n dx = x^(n+1) / (n+1) + C (for n ≠ -1)

Theorems

Power Rule of Integration

Suitable Grade Level

Grades 11-12 or Undergraduate Level