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The given expression is:

\[
- \int 3 \cos(x) \, dx
\]

### Solution:
We can factor out the constant 3 and solve the integral of \(\cos(x)\).

\[
- \int 3 \cos(x) \, dx = -3 \int \cos(x) \, dx
\]

The integral of \(\cos(x)\) is \(\sin(x)\). Therefore:

\[
-3 \int \cos(x) \, dx = -3 \sin(x) + C
\]

Where \(C\) is the constant of integration.

### Final Answer:

\[
-3 \sin(x) + C
\]

Would you like further details or have any questions?

Here are 5 related questions to expand your understanding:
1. What is the integral of \(\sin(x)\)?
2. How do you solve definite integrals involving trigonometric functions?
3. What is the result of integrating a product of trigonometric functions, like \(\int \sin(x) \cos(x) \, dx\)?
4. How would the solution change if you had \(\int 3 \cos(2x) \, dx\) instead?
5. Can you explain how constants affect the integral of trigonometric functions?

**Tip:** Always remember to include the constant of integration, \(C\), when solving indefinite integrals.

Learn how to integrate the expression − ∫ 3 cos(x) dx. This problem involves basic calculus concepts, including the integration of trigonometric functions. Suitable for students in Grades 11-12. Step-by-step solution provided, including important formulas and constants.

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