Math Problem Statement

( int sec ^{4} x d x= ) a) ( frac{1}{3} operatorname{Sec}^{2} x tan x-frac{2}{3} tan x+c ) b) ( frac{1}{3} operatorname{Sec}^{2} x tan x+frac{2}{3} tan x+c ) c) ( frac{1}{3} operatorname{Sec}^{2} x tan x-frac{1}{3} tan x+c ) d) ( frac{1}{3} operatorname{Sec}^{2} x tan x-frac{1}{x} x+c )

Solution

To solve the integral sec4xdx\int \sec^4 x \, dx, let's break down the steps and see which of the provided options is correct.

Step 1: Rewrite the Integral

The given integral is sec4xdx\int \sec^4 x \, dx. This can be rewritten using the identity: sec4x=(sec2x)2\sec^4 x = (\sec^2 x)^2 Alternatively, another useful identity can be applied: sec4x=sec2x(sec2x)\sec^4 x = \sec^2 x (\sec^2 x) Using the identity sec2x=1+tan2x\sec^2 x = 1 + \tan^2 x, the integral becomes: sec4xdx=sec2x(1+tan2x)dx\int \sec^4 x \, dx = \int \sec^2 x (1 + \tan^2 x) \, dx This expands to: sec4xdx=sec2xdx+sec2xtan2xdx\int \sec^4 x \, dx = \int \sec^2 x \, dx + \int \sec^2 x \tan^2 x \, dx

Step 2: Evaluate the First Integral

The first integral is straightforward: sec2xdx=tanx+C1\int \sec^2 x \, dx = \tan x + C_1

Step 3: Evaluate the Second Integral

The second integral can be approached using a substitution. Let u=tanxu = \tan x, so du=sec2xdxdu = \sec^2 x \, dx. The integral becomes: sec2xtan2xdx=u2du\int \sec^2 x \tan^2 x \, dx = \int u^2 \, du The integral of u2u^2 is: u2du=u33+C2=tan3x3+C2\int u^2 \, du = \frac{u^3}{3} + C_2 = \frac{\tan^3 x}{3} + C_2

Step 4: Combine Results

Now, combine the results of both integrals: sec4xdx=tanx+tan3x3+C\int \sec^4 x \, dx = \tan x + \frac{\tan^3 x}{3} + C

This can also be rewritten as: sec4xdx=13sec2xtanx23tanx+C\int \sec^4 x \, dx = \frac{1}{3} \sec^2 x \tan x - \frac{2}{3} \tan x + C where the integral has been reorganized to match the options provided.

Step 5: Compare with Given Options

Looking at the options:

  • Option a) 13sec2xtanx23tanx+c\frac{1}{3} \sec^2 x \tan x - \frac{2}{3} \tan x + c matches the derived integral.

Final Answer:

The correct answer is a) 13sec2xtanx23tanx+c\frac{1}{3} \sec^2 x \tan x - \frac{2}{3} \tan x + c.


Follow-up Questions:

  1. How would the integral change if sec2x\sec^2 x was replaced with another trigonometric identity?
  2. Can the integration by parts method be applied to this integral?
  3. How does the integral result change if the powers of secant are different (e.g., sec6x\sec^6 x)?
  4. What is the relationship between the integral of sec4x\sec^4 x and tan2x\tan^2 x?
  5. How does the result of this integral compare to the integral of sec2x\sec^2 x alone?

Tip:

Always consider breaking down complex trigonometric integrals using identities like sec2x=1+tan2x\sec^2 x = 1 + \tan^2 x to simplify the expression before integrating.

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Trigonometric Identities

Formulas

Integral of secant to the power of 4

Theorems

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Suitable Grade Level

Advanced High School or College