Math Problem Statement

exdxex+5\int\frac{e^{x}dx}{e^{x}+5}

Solution

To solve the integral

exdxex+5\int \frac{e^x \, dx}{e^x + 5}

we can use the substitution method. Let's proceed with the following steps:

Step 1: Choose a substitution

Let u=ex+5.u = e^x + 5.

Then, the derivative of uu with respect to xx is: dudx=exdu=exdx.\frac{du}{dx} = e^x \Rightarrow du = e^x \, dx.

This substitution transforms the integral into:

exdxex+5=duu.\int \frac{e^x \, dx}{e^x + 5} = \int \frac{du}{u}.

Step 2: Integrate with respect to uu

Now we have a simpler integral: duu=lnu+C,\int \frac{du}{u} = \ln |u| + C, where CC is the constant of integration.

Step 3: Substitute back in terms of xx

Since u=ex+5u = e^x + 5, we can write the solution as: lnex+5+C.\ln |e^x + 5| + C.

Final Answer

exdxex+5=lnex+5+C.\int \frac{e^x \, dx}{e^x + 5} = \ln |e^x + 5| + C.

Would you like a deeper explanation of any part of this solution?

Here are five related questions you may find interesting:

  1. How would the approach differ if there was an extra constant multiplied with exe^x in the denominator?
  2. Can this integral be solved with other techniques like partial fractions?
  3. What happens if we integrate e2xdxex+5\int \frac{e^{2x} \, dx}{e^x + 5}?
  4. How does changing the constant in the denominator affect the integration result?
  5. How would the solution change if we had exdxe2x+5\int \frac{e^{x} \, dx}{e^{2x} + 5} instead?

Tip: Substitution is a powerful method in integration; always look for expressions in the integrand that can simplify through derivatives!

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Math Problem Analysis

Mathematical Concepts

Calculus
Integration
Substitution Method

Formulas

Integral of 1/u with respect to u: \( \int \frac{1}{u} \, du = \ln |u| + C \)

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

College Calculus or Advanced High School Calculus