The integral of $\cos x$ is:

$\int \cos x \, dx = \sin x + C$

Explanation:

• The derivative of $\sin x$ is $\cos x$, so the antiderivative (integral) of $\cos x$ is $\sin x$.
• $C$ is the constant of integration, since this is an indefinite integral.

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Would you like me to show step-by-step reasoning or apply this to a specific interval (definite integral)?

Related Questions

1. What is the integral of $\cos(2x)$?
2. How do you evaluate $\int \cos x \, dx$ from $x = 0$ to $x = \pi$?
3. What is the integral of $\sin x$?
4. How do you solve $\int e^{\cos x} \sin x \, dx$?
5. Can you find the second derivative of $\sin x$?

Tip

Always check if you need a definite or indefinite integral before solving—it changes the process and the result.