Math Problem Statement

Demonstrate how to find the integral ∫ 9xe^(5x) dx.

Solution

The problem in the image asks to "Demonstrate how to find the integral" of the expression:

9xe5xdx\int 9xe^{5x} \, dx

Solution: Integration by Parts

This integral can be solved using integration by parts. The formula for integration by parts is:

udv=uvvdu\int u \, dv = uv - \int v \, du

  1. Choose uu and dvdv:

    • Let u=xu = x, which implies du=dxdu = dx.
    • Let dv=9e5xdxdv = 9e^{5x} \, dx, which implies that we need to find vv by integrating dvdv.
  2. Find vv: v=9e5xdx=95e5xv = \int 9e^{5x} \, dx = \frac{9}{5} e^{5x} (since the integral of eaxe^{ax} is 1aeax\frac{1}{a} e^{ax}).

  3. Apply the integration by parts formula: Using the formula udv=uvvdu\int u \, dv = uv - \int v \, du: 9xe5xdx=x95e5x95e5xdx\int 9xe^{5x} \, dx = x \cdot \frac{9}{5} e^{5x} - \int \frac{9}{5} e^{5x} \, dx

  4. Simplify the remaining integral: 95e5xdx=925e5x\int \frac{9}{5} e^{5x} \, dx = \frac{9}{25} e^{5x}

  5. Final result: Substituting this back, we get: 9xe5xdx=95xe5x925e5x+C\int 9xe^{5x} \, dx = \frac{9}{5} x e^{5x} - \frac{9}{25} e^{5x} + C where CC is the constant of integration.

Thus, the integral of 9xe5xdx9xe^{5x} \, dx is:

95xe5x925e5x+C\boxed{\frac{9}{5} x e^{5x} - \frac{9}{25} e^{5x} + C}

Would you like further explanation or have any specific questions on the process?

Related Questions:

  1. How does integration by parts work for other types of functions like logarithmic or trigonometric ones?
  2. What are the conditions under which integration by parts is the best technique to use?
  3. How can we verify the result of an integral using differentiation?
  4. Can we generalize this process for integrals involving higher powers of xx?
  5. What is the impact of different coefficients in the exponential term (e.g., eaxe^{ax}) on the integration?

Tip:

When selecting uu in integration by parts, it's

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Calculus
Integration by Parts
Exponential Functions

Formulas

Integration by Parts: ∫ u dv = uv - ∫ v du

Theorems

Integration by Parts Theorem

Suitable Grade Level

College Level (Calculus II)