You are given the equation:

$\sum_{n=1}^{\infty} (\sin(2n x) + \cos(2n x)) = 2$

Steps to Solve:

1. The equation involves an infinite sum of trigonometric functions. Let's break it down into manageable parts.

2. The sum involves the terms $\sin(2n x) + \cos(2n x)$, which are oscillatory functions. Since this is an infinite series, we need to examine if this sum converges and if there is a way to simplify it.

3. Using a known trigonometric identity: $\sin(A) + \cos(A) = \sqrt{2} \sin(A + \pi/4)$ we could rewrite each term as a phase-shifted sine function, but the infinite sum remains complex.

4. It's important to investigate the nature of this infinite series. Typically, such sums may require Fourier series techniques or complex analysis to fully resolve.

Would you like a more detailed explanation of how to tackle this type of series in detail or have any specific questions?

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5 Related Questions:

1. How do you analyze the convergence of an infinite series involving sine and cosine functions?
2. What are the steps for simplifying trigonometric sums involving infinite terms?
3. How does Fourier series analysis apply to solving trigonometric sums?
4. What are common strategies for solving equations involving infinite sums?
5. Could complex numbers simplify the analysis of trigonometric sums?

Tip: Infinite series involving trigonometric functions often require advanced techniques, such as Fourier series or complex exponential forms, to solve efficiently.