Math Problem Statement
sin(x-1)的积分表达式
Solution
对函数 进行不定积分,按照积分规则来求解:
我们可以通过变量替换法进行解题。令 ,则有:
因此,积分可以重写为:
再将 代回:
因此, 的不定积分表达式为:
相关问题:
- 如何对 进行不定积分?
- 如何对三角函数的乘积进行积分?
- 如果已知定积分区间,如何求 的定积分?
- 如何使用分部积分法处理三角函数?
- 如何求 的积分?
提示:
积分中变量替换法是一种非常常见且实用的技巧,适用于许多类型的积分问题。
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Math Problem Analysis
Mathematical Concepts
Calculus
Integration
Trigonometric Functions
Formulas
∫sin(u) du = -cos(u) + C
u-substitution: u = x - 1
Theorems
Fundamental Theorem of Calculus
Integration by Substitution
Suitable Grade Level
Grades 11-12, College Level Calculus
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