Math Problem Statement

The points O(9, -3), P(6, 1), Q(2, -2), and R(5, -6) form quadrilateral OPQR. Plot the points then find the slopes and lengths, and identify the type of quadrilateral.

Solution

Let's go step by step to solve the problem based on the image.

Points:

  • O(9,3)O(9, -3)
  • P(6,1)P(6, 1)
  • Q(2,2)Q(2, -2)
  • R(5,6)R(5, -6)

Part 1: Slopes

We will calculate the slope of each pair of points using the slope formula: slope of line=y2y1x2x1\text{slope of line} = \frac{y_2 - y_1}{x_2 - x_1}

1. Slope of OPOP:

Points O(9,3)O(9, -3) and P(6,1)P(6, 1) slope of OP=1(3)69=43=43\text{slope of } OP = \frac{1 - (-3)}{6 - 9} = \frac{4}{-3} = -\frac{4}{3}

2. Slope of PQPQ:

Points P(6,1)P(6, 1) and Q(2,2)Q(2, -2) slope of PQ=2126=34=34\text{slope of } PQ = \frac{-2 - 1}{2 - 6} = \frac{-3}{-4} = \frac{3}{4}

3. Slope of QRQR:

Points Q(2,2)Q(2, -2) and R(5,6)R(5, -6) slope of QR=6(2)52=43=43\text{slope of } QR = \frac{-6 - (-2)}{5 - 2} = \frac{-4}{3} = -\frac{4}{3}

4. Slope of RORO:

Points R(5,6)R(5, -6) and O(9,3)O(9, -3) slope of RO=3(6)95=34\text{slope of } RO = \frac{-3 - (-6)}{9 - 5} = \frac{3}{4}

Part 2: Lengths

We will calculate the lengths using the distance formula: distance=(x2x1)2+(y2y1)2\text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

1. Length of OPOP:

length of OP=(69)2+(1(3))2=(3)2+(4)2=9+16=25=5\text{length of } OP = \sqrt{(6 - 9)^2 + (1 - (-3))^2} = \sqrt{(-3)^2 + (4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5

2. Length of PQPQ:

length of PQ=(26)2+(21)2=(4)2+(3)2=16+9=25=5\text{length of } PQ = \sqrt{(2 - 6)^2 + (-2 - 1)^2} = \sqrt{(-4)^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5

3. Length of QRQR:

length of QR=(52)2+(6(2))2=(3)2+(4)2=9+16=25=5\text{length of } QR = \sqrt{(5 - 2)^2 + (-6 - (-2))^2} = \sqrt{(3)^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5

4. Length of RORO:

length of RO=(95)2+(3(6))2=(4)2+(3)2=16+9=25=5\text{length of } RO = \sqrt{(9 - 5)^2 + (-3 - (-6))^2} = \sqrt{(4)^2 + (3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5

Part 3: Identifying the Quadrilateral

Since all sides are equal in length and opposite sides are parallel (as indicated by equal slopes), the quadrilateral is a rhombus.

Final Answer:

  • Slope of OP=43OP = -\frac{4}{3}
  • Slope of PQ=34PQ = \frac{3}{4}
  • Slope of QR=43QR = -\frac{4}{3}
  • Slope of RO=34RO = \frac{3}{4}
  • Length of OP=5OP = 5
  • Length of PQ=5PQ = 5
  • Length of QR=5QR = 5
  • Length of RO=5RO = 5
  • Quadrilateral OPQR is best described as a rhombus.

Would you like more details or have any questions?

Related Questions:

  1. How do you prove a quadrilateral is a square using slopes and lengths?
  2. What is the relationship between parallel lines and their slopes?
  3. How can you calculate the area of a rhombus given its diagonals?
  4. How does the distance formula relate to the Pythagorean theorem?
  5. What distinguishes a rhombus from a parallelogram?

Tip:

For any quadrilateral, verifying both the side lengths and the angles formed by slopes helps confirm the specific type of quadrilateral (e.g., square, rhombus, or rectangle).

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Slope of a Line
Distance Formula
Properties of Quadrilaterals

Formulas

Slope of a line: (y2 - y1) / (x2 - x1)
Distance formula: √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Properties of a Rhombus
Parallel Lines have Equal Slopes

Suitable Grade Level

Grades 8-10